Answer:
False
Explanation:
Although college is almost essential in our day and age in order to become successful in the feild, some careers, very few do not need the requirement.
Christopher columbus is it?
Answer:
x/ y = -2/ 3
Explanation:
we have:
3(x + y) = y
<em>distributing</em><em> </em><em>3</em><em> </em><em>within</em><em> </em><em>the</em><em> </em><em>parenthesis</em><em>:</em>
<em>=</em><em>></em><em> </em>3x + 3y = y
<em>taking y to the other side, changing its sign in the process</em>
=> 3x = y - 3y
=> 3x = y(1 - 3)
=> 3x = -2y
<em>you</em><em> </em><em>can</em><em> </em><em>represent</em><em> </em><em>any</em><em> </em><em>integer</em><em> </em><em>as</em><em> </em><em>a</em><em> </em><em>fraction</em><em> </em><em>by</em><em> </em><em>putting</em><em> </em><em>a</em><em> </em><em>"</em><em>1</em><em>"</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>denominator</em>
![\implies \mathsf{ \frac{3x}{1} = - \frac{2y}{1} }](https://tex.z-dn.net/?f=%20%5Cimplies%20%5Cmathsf%7B%20%5Cfrac%7B3x%7D%7B1%7D%20%20%3D%20%20-%20%20%5Cfrac%7B2y%7D%7B1%7D%20%7D)
<em>taking</em><em> </em><em>y</em><em> </em><em>to</em><em> </em><em>th</em><em>e</em><em> </em><em>denominator</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>LHS</em><em> </em><em>and</em><em> </em><em>3</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>denominator</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>RHS</em>
![\implies \mathsf{ \frac{x}{y} = - \frac{2}{3} }](https://tex.z-dn.net/?f=%20%5Cimplies%20%5Cmathsf%7B%20%5Cfrac%7Bx%7D%7By%7D%20%3D%20%20%20-%20%5Cfrac%7B2%7D%7B3%7D%20%20%7D)
that makes the ratio, x/y = -2/ 3
______________
Hope this helps!
Answer:
5.43 miles
Explanation:
Required
Determine the distance from school to her home
Given.
[When going to school]
![Speed = 6mph](https://tex.z-dn.net/?f=Speed%20%3D%206mph)
Represent time with t
Distance is calculated as:.
![Distance = Speed * Time](https://tex.z-dn.net/?f=Distance%20%3D%20Speed%20%2A%20Time)
![Distance = 6 * t](https://tex.z-dn.net/?f=Distance%20%3D%206%20%2A%20t)
![Distance = 6t](https://tex.z-dn.net/?f=Distance%20%3D%206t)
[When coming back from school]
![Speed = 35mph](https://tex.z-dn.net/?f=Speed%20%3D%2035mph)
![Time = \¾\ hour\ lesser](https://tex.z-dn.net/?f=Time%20%3D%20%5C%C2%BE%5C%20hour%5C%20lesser)
This implies that she spends t - ¾hr when coming back from school.
So,
becomes
![Distance = 35 * (t - \¾)](https://tex.z-dn.net/?f=Distance%20%3D%2035%20%2A%20%28t%20-%20%5C%C2%BE%29)
![Distance= 35(t - \¾)](https://tex.z-dn.net/?f=Distance%3D%2035%28t%20-%20%5C%C2%BE%29)
[Equate both expressions of distance]
![35(t - \¾) = 6t](https://tex.z-dn.net/?f=35%28t%20-%20%5C%C2%BE%29%20%3D%206t)
[Open Bracket]
![35t - 35 * \¾ = 6t](https://tex.z-dn.net/?f=35t%20-%2035%20%2A%20%5C%C2%BE%20%3D%206t)
![35t - 26.25 = 6t](https://tex.z-dn.net/?f=35t%20-%2026.25%20%3D%206t)
[Collect like terms]
![35t - 6t = 26.25](https://tex.z-dn.net/?f=35t%20-%206t%20%3D%2026.25)
![29t = 26.25](https://tex.z-dn.net/?f=29t%20%3D%2026.25)
[Solve for t]
![t = \frac{26.25}{29}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B26.25%7D%7B29%7D)
![t =0.91](https://tex.z-dn.net/?f=t%20%3D0.91)
[Substitute 0.91 for t in]
![Distance = 6t](https://tex.z-dn.net/?f=Distance%20%3D%206t)
![Distance = 6 * 0.91](https://tex.z-dn.net/?f=Distance%20%3D%206%20%2A%200.91)
![Distance = 5.43\ miles](https://tex.z-dn.net/?f=Distance%20%3D%205.43%5C%20miles)
<em>Hence, the school is 5.43 miles from her home</em>