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GrogVix [38]
3 years ago
15

2. In an experiment, a fixed amount of fertilizer was applied to each of 10 plots, and

SAT
1 answer:
Shtirlitz [24]3 years ago
8 0

yeah so basically its corresponding with ur mom lol

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Assume that there is a 6​% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit
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The easiest way to do this is calculate the probability that all drives crash, and subtract that from one. The first one is .06 squared subtracted from 1, so it’s .9964 or 99.64%. The second one is .06 cubed subtracted from 1, so it’s .9998, or 99.98 %
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Why grade 12 learners should write their nbts as early as possible
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Answer: help to interpret your NSC results and can be used by universities in different ways. so these are two reasond.

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2 years ago
Which equation best represents the line of best fit for the scatterplot? a) y = 2x b) y = 2x + 2 c) y = −2x + 2 d) y = −x + 2
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The equation which best represents the line of best fit for the scatterplot in the image attached below is: B. y = 2x + 2.

<h3>What is a scatter plot?</h3>

A scatter plot refers to a type of graph which uses the cartesian coordinates (x-axis and y-axis) to illustrate the values of two variables, with the resulting points revealing any correlation between the set of data.

Based on the graph attached in the image below, y = 2x + 2 is an equation which best represents the line of best fit for the scatterplot because there is a corellation between the data at this point.

Read more on scatterplot here: brainly.com/question/6592115

6 0
1 year ago
A study of a population showed that Male'S body temperature are approximately normally distributed with a mean of 98.4°F and a p
Ilia_Sergeevich [38]

Answer:

The body temperature of a male at the 83rd percentile is 98.8°F.

Explanation:

The <em>n</em>th percentile implies that there are <em>n%</em> value below this percentile value.

That is, if P (<em>X </em><<em> x</em>) = n% then <em>x</em> is the <em>n</em>th percentile.

Let<em> </em><em>X</em> = male body temperature.

The random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 98.4°F and standard deviation, <em>σ</em> = 0.40°F.

Let <em>x</em> be the 83rd percentile value.

Then, P (X < x) = 0.83.

The value of <em>x</em> can be computed from the <em>z</em>-score.

z=\frac{x-\mu}{\sigma}

Compute the <em>z</em>-score related to this probability as follows:

P (Z < z) = 0.83

*Use the <em>z</em>-table for the <em>z</em>-score.

The value of <em>z</em> is 0.95.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\0.96=\frac{x-98.4}{0.40} \\x=98.4+(0.96\times0.40)\\=98.784\\\approx98.8

Thus, the body temperature of a male at the 83rd percentile is 98.8°F.

8 0
3 years ago
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