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AleksAgata [21]
2 years ago
12

Help please I'm no good at this​

Mathematics
1 answer:
viva [34]2 years ago
6 0

Here are the completed tables

Gallons Quart

1               4

2               8

5               20

7               28

Quart    Pint

1             2

3             6

6           12

8            16

Pint  Cup

1          2

3         6

5        10

9       18

The capacity of the objects are:

Swimming pool - 5000 gallons

Watering can - 8 quarts

Juice box - 2 pints

Soup bowl - 2 cups

The measurement from least to greatest is: 6 pints, 2 galloons, 18 cups, 6 quart.

<h3>How would the tables be filled?</h3>

In order to fill the tables, the unit of conversion has to be known:

1 gallon = 4 quart

  • 2 gallon = 2 x 4 = 8 quarts
  • 5 gallons : 5 x 4 = 20 quarts
  • 7 gallons: 7 x 4 = 28 quarts

1 quart = 2 pints

6 pint / 2 = 3 quarts

12 / 2 = 6 quarts

8 x 2 = 16 pints

<h3>How to order the measurment from least to largest?</h3>

In order to order the measurement, all the measurements have to be in the same units. All the units would be converted to cups

1 quart = 4 cups

4 x 6 = 24 cups

1 galloon = 16 cups

16 x 2 = 32 cups

1 pint = 2 cups

6 x 2 = 12 cups

To learn how to convert units, please check: brainly.com/question/25993533

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How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
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Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

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To determine the number of sequence, we need to understand how the sequence are generated

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\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

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