The future value of this amounts after 5 years in the order they will be recieved will be:
FV=p(1+r/100)^n
a. $7100
FV=7100(1+9/100)^5
FV=7100(1.09)^5
FV=$10,924.23
b.$8700
FV=8700(1+9/100)^5
FV=8700(1.09)^5
FV=$ 13,386.03
c. $12500
FV=12500(1+9/100)^5
FV=12500(1.09)^5
FV=$19,232.80
Given:
A biased dice is thrown 300 times.
Table of probabilities of each score.
To find:
The expected number of times the score will be odd.
Solution:
Odd numbers on the dice are 1, 3, 5. The sum of their probability is

Even numbers on the dice are 2, 4, 6. The sum of their probability is

Now, the expected number of times the score will be odd is



Therefore, the expected number of times the score will be odd is 210.
Answer:
r=6.4
Step-by-step explanation:
Get r by itself you need to add 8.5 to get 6.4
Hope this helps (:
⓵ You need to solve the left side first in order to isolate the × and find it’s value :
-7× + 6 = 27
-6 -6
↓
-7× = 21
÷-7 ÷-7
↓
× = -3
If you find it too difficult to divide a number by a negative, just divide 21 by 7 and always remember that when dividing, when the signs are different the answer is negative. So knowing that you could just divide 21 by 7, which is 3, and add a negative sign in front!
I hope this helped, if there’s anything let me know! ☻
Answer:
12.167
Step-by-step explanation: