Answer:
A is y-4 x-4
B is y-3 x-2
C is y-1 x-2
D is y-1 x-4
Step-by-step explanation:
look at where they are lined up from y to x
Answer:
The answer to your question is cost of 0.6 pound of candy $4.17
Step-by-step explanation:
Data
1 pound of candy = $6.95
only 0.6 pounds
final cost = ?
Process
1.- Use proportions to find the cost of 0.6 pounds of candy
1 pound of candy -------------- $6.95
0.6 pound of candy ---------- x
2.- Use cross multiplication
x = (0.6 x 6.95) / 1
3.- Simplification and result
x = $ 4.17
Answer:
They performed the same, with 80% for both of their marks.
Step-by-step explanation:
Rashmi's mark in percentage : (480/600) x 100 = 80%
Rajan's Mark in percentage : (560/700) x 100 = 80%
To find anyone's marks in percentage, you can use :
(marks scored/full marks) x 100.
Membership Fitness Charges: $30.00 per Month
All Day Fitness Club Charges: $22.00 per Month
Initiation Fee : $80.00
Equation:
30T = 22T + 80 ========> T = 10 Months
Lets solve your equation step-by-step.
30t = 22t + 80
Step 1: Subtract 22t from both sides.
30t − 22t = 22t + 80 − 22t
8t = 80
Step 2: Divide both sides by 8.
8t / 8 = 80 / 8
Answer ==========> T = 10 Months Will the total amount paid to the two fitness clubs will be the same.
Hope that helps!!!!!!!!!!! : )
Answer:
9. <em><u>1</u></em><em><u>0</u></em>
10. <em><u>1</u></em><em><u>0</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>
11.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>
12.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>1</u></em><em><u>0</u></em>
Step-by-step explanation:
9.<em><u>U</u></em><em><u>sing </u></em><em><u>Pythagoras</u></em><em><u> Theorem</u></em>
<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>√</u></em><em><u>(</u></em><em><u>H</u></em><em><u>²</u></em><em><u>-</u></em><em><u>B</u></em><em><u>²</u></em><em><u>)</u></em>
<em><u>Where</u></em><em><u>,</u></em>
<em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>perpendicular</u></em><em><u> </u></em>
<em><u>B </u></em><em><u>=</u></em><em><u> </u></em><em><u>Base</u></em>
<em><u>H </u></em><em><u>=</u></em><em><u> </u></em><em><u>Hypotenuse</u></em>
<em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>H</u></em>
<em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>B/</u></em><em><u>H</u></em>
<em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>B</u></em>
