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algol [13]
2 years ago
13

If the value of a is negative in f(x)=ax^(2), what does the graph look like?

Mathematics
2 answers:
garik1379 [7]2 years ago
7 0

Answer:

A. a parabola that opens down.

Step-by-step explanation:

First we can eliminate two answers, b and d, since parabalas that open left or right use the y variable.

Now the equation of a standard parabola is x². This means that there are no negative y values, and therefore it cannot open down, it is up.

With a NEGATIVE coefficient, the graph is flipped over the x axis, therefore making it open down.

Graphical proof is attached for further understanding, positive a is in red, negative a is in blue.

borishaifa [10]2 years ago
4 0

Answer:

it opens down, thats the answer

Step-by-step explanation:

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there were 60 people in the town's first annual parade. That number has been growing by about 5% each year. predict the number o
Zepler [3.9K]

Answer: thanks for the points

Step-by-step explanation

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3 0
2 years ago
What is the nth term of quadratic sequence 4 7 12 19 28
Anni [7]
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:

Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².

We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.

Now we find the difference between the actual terms of the sequence and the numbers we just found:

4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.

Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
7 0
3 years ago
The game of Connex contains one 4-unit piece, two identical 3-unit pieces, three identical 2-unit pieces and four identical 1-un
Aleks [24]

Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

= 20permutations

4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

= 5*6

= 30 permutations

6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

= 30 permutations

Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

= 5*4

= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

= 6*10

= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

5 0
2 years ago
Vertex Form of Quadratic Functions
Nikitich [7]
The X-intercepts: (1,0),(-7,0)

Axis of symmetry: x= - 3

The vertex: (-3, -8)

The Y-intercept: (0, -7/2)

Concave up or down: concave up

Sketch: a poorly drawn picture on the bottom.

I hope that helps.

8 0
3 years ago
HELPP PLEASEEEEEEE
Alexxx [7]
A, c, and d
plug in each x in the equation and it should equal the y value
7 0
2 years ago
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