Answer:
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hope this is helpful for you
Answer:
475.
Step-by-step explanation:
We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.
We will use z-score formula and normal distribution table to solve our given problem.
Top 60% means greater than 40%.
Let us find z-score corresponding to normal score to 40% or 0.40.
Using normal distribution table, we got a z-score of .
Upon substituting our given values in z-score formula, we will get:
Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.
Answer:
p=1
Step-by-step explanation:
Given that a day care program has an average daily expense of $75.00. The standard deviation is $5.00.
Sample size = 64
Std error of sample =
Thus sample mean will follow normal with
(75, 0.625)
Required probability
=
It is almost a certain event with p =1
Answer:
10 inches.
Step-by-step explanation:
First we need to find what is the bigger dimension of the box, because the relay baton will occupy the box, and the larger dimension of the relay baton (that is, it's length) need to be less or equal than the larger dimension of the box.
The dimensions of the box are: 4 inches, 6 inches and 10 inches.
The larger dimension of the box is 10 inches. So, If we want the relay baton to fit in the box, the maximum length it can have is 10 inches.