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Misha Larkins [42]
2 years ago
7

Which algebraic expression represents “the sum of a number and 9”?

Mathematics
1 answer:
Kipish [7]2 years ago
4 0

Answer:

9+n or n+9

Step-by-step explanation:

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MATHEMATICS IN YOUR AREA HURRY UP
beks73 [17]
The answer is 1 g
If that is correct
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1 year ago
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Factorise this : 2p²-p-10
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

p(2p-1)-10

8 0
2 years ago
Write the equation of a line that passes through points (0,4) and (-2,-3) in slope intercept form
Otrada [13]

y=mx+b is the equation of a line;

m=slope , b= y-intercept

You can find the slope with this following equation: (y(2)-y(1))/(x(2)-x(1))

In this case the points are (0,4) and (-2,-3). The first set being (0,4) and the second (-2,-3). This means (0,4) can be expressed as (x(1),y(1)) and (-2,-3) expressed as (x(2),y(2)). Plugging these numbers into the slope equation gives us: (-3-4)/(-2-0) = -7/-2 = 7/2.

m= 7/2 ; so we have : y= (7/2)x+b

We are give a set of points which it passes through, we can simply plug them in:

4 = (7/2)(0)+b (0 is the x and 4 is the y)

We get 4 = 0 +b .... 4=b

our final equation is : y=(7/2)x+4

4 0
3 years ago
The claim is that the white blood cell counts of adult females are normally​ distributed, with a standard deviation equal to 1.6
loris [4]
The population standard deviation, σ = 1.68, the sample standard deviation, s = 1.95, the sample mean =7.23,  and the sample size, n = 39.The test statistics is given by
T=(n - 1) (s / σ)²
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3 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 409 green peas and 171 yellow peas. Use a 0.05
grigory [225]
The usual expectation for this kind of experiment is that the peas would yield green and yellow peas in a 3:1 ratio, or 75% green to 25% yellow. So your null hypothesis is that the proportion of yellow peas is p=0.25.

You're testing the claim that 26% of the offspring will be yellow, which means the alternative hypothesis is that the proportion of yellow peas is actually 0.26, or more generally that the expected proportion is greater than 0.25, or p>0.25.

The test statistic in this case will be

Z=\dfrac{\hat p-p_0}{\sqrt{\dfrac{p_0(1-p_0)}n}}

where p_0 is the proportion assumed under the null hypothesis, \hat p is the measured proportion, and n is the sample size. You have p_0=0.25, \hat p=\dfrac{171}{171+409}\approx0.29, and n=409+171=580, so the test statistic is

Z=\dfrac{0.29-0.25}{\sqrt{\dfrac{0.25\times0.75}{580}}}\approx2.2247

Because you're testing p>p_0, this is a right-tailed test, so the P-value is

\mathbb P(Z>2.2247)\approx0.0131

The critical value for a right-tail test at a 0.05 significance level is Z_\alpha\approx1.6449, which means the rejection region is any test statistic that is larger than this critical value. Since Z>Z_\alpha in this case, we reject the null hypothesis.

So the conclusion for this test is that the sample proportion is indeed statistically significantly different from the proportion suggested by the null hypothesis.
8 0
3 years ago
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