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12345 [234]
2 years ago
10

Pls help thank you!!

Mathematics
1 answer:
ser-zykov [4K]2 years ago
5 0
Answer: Nationalism.
It would to American expansion because a country that is honest and loyal
is respected and when it is people will feel comfortable living in it.



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It is the answer choice c)
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3 years ago
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In May 2019 the average price of a liter of milk in France was 1.09 euros. Given that a liter is equivalent to 0.264172 US gallo
cestrela7 [59]

9514 1404 393

Answer:

  $4.64/gal

Step-by-step explanation:

€1.09/(1 L) × $1/(€0.89) × (1 L)/(0.264172 gal) ≈ $4.64/gal

__

To convert units, multiply by a fraction that has numerator and denominator equal, but with different units. The units you don't want should be placed in the fraction so they cancel the units in the measure you're converting.

Here, we want <em>dollars per gallon</em>. So, we start with the currency value and quantity we're given: <em>euros per liter</em>.

Since euros is in the numerator and we want dollars there, we multiply by a fraction that has dollars in the numerator and euros in the denominator: $1/€0.89.

We have liters in the denominator and we want gallons there. We can cancel the liters unit by putting it in the numerator of our conversion factor: (1 L)/(0.264172 gal).

Multiplying euros per liter by these two conversion factors give us the equivalent in dollars per gallon.

5 0
3 years ago
The manufacturers of m&amp;m's claim that 20% of the milk chocolate m&amp;m candies are orange. find the mean and standard devia
lora16 [44]
T<span>he mean of a sampling distribution of a sample with proportion, p and sample size, n is given by \mu=np.

</span>T<span>he standard deviation of a sampling distribution of a sample with proportion, p and sample size, n is given by \sigma= \sqrt{np(1-p)}

</span>Given that t<span>he manufacturers of m&m's claim that 20% of the milk chocolate m&m candies are orange. The proportion is p = 0.2

The mean of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by \mu=100(0.2)=20

</span><span>The standard deviation of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by \sigma= \sqrt{100(0.2)(1-0.2)} = \sqrt{16} =4</span>

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3 years ago
4+20÷2+2=<br><br>PLS ANSWER 30 POINTS TO WHOEVER ANSWERS FIRST
nadezda [96]

Answer:

16

Step-by-step explanation:

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2 years ago
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A quantity of food would last a family of 5 for 21days. How long would the same quantity last a family of 7 if they all eat at t
Diano4ka-milaya [45]
15 days
5x21=105 the amount of food they have
105/7=15 days of food for a family of 7
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