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svlad2 [7]
3 years ago
9

Determine a series of transformations that would map Figure RR onto Figure SS.

Mathematics
1 answer:
nadezda [96]3 years ago
3 0

Answer:

transformation

Step-by-step explanati

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\dfrac{4}{9}(x+3)=g\ \ \ \ |multiply\ both\ sides\ by\ 9\\\\4(x+3)=9g\ \ \ \ |use\ distributive\ property:a(b+c)=ab+ac\\\\4x+12=9g\ \ \ \ |subtract\ 12\ from\ both\ sides\\\\4x=9g-12\ \ \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{x=\frac{9}{4}g-3}
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Find the volume of a cone it is h9 r=4
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r: 4
Perimeter: u: 25.133
Base area: g: 50.265
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3 years ago
Sarah lost her science book. Her school charges a lost book fee equal to 75% of the cost of the book. Sarah received a notice st
Scorpion4ik [409]

Answer: the school paid $80 for the book.

Step-by-step explanation:

Let x represent the amount that the school paid for the book.

Her school charges a lost book fee equal to 75% of the cost of the book. It means that the amount that the school would charge on a book that cost $x is

75/100 × x = 0.75 × x = 0.75x

Sarah received a notice stating that she owed the school $60 for he lost book. It means that

0.75x = 60

x = 60/0.75

x = $80

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Pls help I’m in 3rd grade<br> I need help plss
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Step-by-step explanation:

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A system has a continuous load requirement of 80 MW. Find the expected load loss and the probability of load loss (loss of load
MariettaO [177]

Answer:

Expected load loss = 1.35

P (Load Loss) = 0.127

Step-by-step explanation:

The probability of failure is: <em>q</em> = 0.015

The probability of success is: <em>p</em> = 1 - <em>q</em> = 1 - 0.015 = 0.985

The number of units the generation system is composed of is, <em>n</em> = 9.

The capacity of each unit is 10 MW.

Let <em>X</em> = number of units that failed or are unavailable.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>q.</em>

The probability function is:

P (X=x)={n\choose x}p^{x}(1-p)^{n-x}; <em>x</em> =0, 1, 2, 3...

  • The expected number of failures is:

E(X)=nq=9\times0.015=0.135

Then the expected load loss is:

E (Load\ Loss)=10\times E(X)=10\times 0.135=1.35

Thus, the expected load loss is 1.35.

  • The load loss will be when at least one unit fails.

The probability that at least one unit fails is:

P (X ≥ 1) = 1 - P (X < 1) = 1 - P (X = 0)

             =1-[{9\choose 0}(0.015)^{0}(1-0.015)^{9-0}]\\=1-0.8728\\=0.12718\\\approx0.127

Thus, the probability of load loss is 0.127.

5 0
3 years ago
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