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Arada [10]
2 years ago
5

Graphs of Function,

Mathematics
1 answer:
andrew-mc [135]2 years ago
5 0

Answer:

A function is increasing when the gradient is positive

A function is decreasing when the gradient is negative

<u>Question 7</u>

If you draw a tangent to the curve in the interval x < -2 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve in the interval x > -2 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -2 will be zero.

The function is increasing when x < -2

(- \infty,-2)

The function is decreasing when x > -2

(-2, \infty)

<u>Additional information</u>

We can actually determine the intervals where the function is increasing and decreasing by differentiating the function.

The equation of this graph is:

f(x)=-2x^2-8x-8

\implies f'(x)=-4x-8

The function is increasing when f'(x) > 0

\implies -4x-8 > 0

\implies -4x > 8

\implies x < -2

The function is decreasing when f'(x) < 0

\implies -4x-8 < 0

\implies -4x < 8

\implies x > -2

This concurs with the observations made from the graph.

<u>Question 8</u>

This is a straight line graph. The gradient is negative, so:

The function is decreasing for all real values of x

(- \infty,+ \infty)

But if they want the interval for the grid only, it would be -4 ≤ x ≤ 1

[-4,1]

<u>Question 9</u>

If you draw a tangent to the curve in the interval x < -1 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve in the interval x > -1 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -1 will be zero.

The function is decreasing when x < -1

(- \infty,-1)

The function is increasing when x > -1

(-1, \infty)

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Answer:

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<u>so </u>

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Step-by-step explanation:

<em>Expression to finds Jamal’s height in dekameters </em>

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The values of the trigonometry ratios are:

  • cos α = - 5/13 and cot α = 5/12
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<h3>How to solve the trigonometry ratios?</h3>

<u>1: sin α = -12/13 and tan α > 0, find cos α and cot α</u>

Because tan α > 0, then it means that cos α and sin α are negative

So, we have:

sin²α + cos²α = 1

Substitute sin α = -12/13

(-12/13)² + cos²α = 1

This gives

cos²α = 1 - (-12/13)²

Evaluate the squares

cos²α = 1 - 144/169

Evaluate the difference

cos²α = 25/169

Take the square root of both sides

cos α = - 5/13

The cotangent ratio is represented as:

cot α = cos α/sin α

This gives

cot α = (-5/13)/(-12/13)

Evaluate

cot α = 5/12

Hence, cos α = - 5/13 and cot α = 5/12

<u>2: tan α = -12/5 for α in quadrant IV, find sec α and cot α</u>

Because α is in quadrant IV, then it means that sec α is positive

cot α = 1/tan α

This gives

cot α = 1/(-12/5)

Evaluate

cot α = -5/12

Also, we have:

sec²α = 1 + tan²α

Substitute tan α = -12/5

sec²α = 1 + (-12/5)²

Evaluate the squares

sec²α = 1 + 144/25

Evaluate the sum

sec²α = 169/25

Take the square root of both sides

sec α = 13/5

Hence, cot α = -5/12 and sec α = 13/5

Read more about trigonometry ratios at:

brainly.com/question/11967894

#SPJ1

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