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Answer: A) 5</h3>
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Explanation:
Angle B = 90 degrees, and the side opposite this is the hypotenuse AC = 10.
Angle C = 30, and the side opposite this smallest angle is AB. For now we'll call this x.
It turns out that for any 30-60-90 triangle, the hypotenuse is twice as long as the short leg. So if x is the short leg, then 2x is the hypotenuse.
Set 2x equal to the given hypotenuse 10 and solve for x
2x = 10
x = 10/2
x = 5
That makes AB = 5.
In other words, we cut the hypotenuse in half to get the length of the shorter leg.
Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
Δx (delta x) is about a secant line, a line between two points representing the rate of change between those two points. That's a "differential" (between the two points).
dx is about a tangent line to one point, representing an instantaneous rate of change. That makes it a "derivative."
Answer:
3 units
Step-by-step explanation:
Answer:
If the transversal cuts across parallel lines (the usual case) then alternate exterior angles have the same measure. So in the figure above, as you move points A or B, the two alternate angles shown always have the same measure.
Step-by-step explanation:
Hope this helps
