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3 years ago

7

What can be said of the result if a negative is raised to an odd power?

1 answer:

mel-nik [20]3 years ago

6 0

Let's say we have the base -2 and we raise it to the third power, what will happen?

Well, $-2^3 = -2 * -2 * -2$ .

$-2 * -2 * -2 = (-2 * -2) * -2 = (4) * -2 = -8$

Any negative base with an odd exponent will result in a negative answer, because, unlike even exponents and negative bases, the negatives will not cancel out.

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Simplify (Remember to simplify means to write an equivalent expression that uses each variable on')

DaniilM [7]

Answer:

A) $x^{3} y^{4}$

B) $-\frac{5x^{2} }{y}$

C) $9m^{4}n^{4}$

D) $\frac{1}{x^{3} }$

Step-by-step explanation:

Hope this helps.

6 0

3 years ago

Help me real answers

Slav-nsk [51]

That is a vertical stretch by 2

8 0

3 years ago

Write and simplify the integral that gives the arc length of the following curve on the given interval b. If necessary, use tech

LiRa [457]

Answer:

L = 4.103

Step-by-step explanation:

we have length of curve

$L = \int\limits^b_a {\sqrt{(f'(x))²+1} } \, dx$

where $f(x) = d/dx(3*in(x)) = 3/x$

substituting for f(x), we have $L = \int\limits^5_2 {\sqrt{(3/x)²+1} } \, dx$

(since the limit is 2≤ x ≤5)

solving, $L = \int\limits^5_2 {\sqrt{9/x²+1} } \, dx$

Simplifying this integral, we have

L = 4.10321

8 0

4 years ago

Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions

Pachacha [2.7K]

Answer:

$132\ in^{2}$ is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

$L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in$

$W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in$

$H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in$

<em>Find the area of the base B</em>

$B=LW$

$B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}$

<em>Find the perimeter of the base P</em>

$P=2(L+W)$

$P=2(\frac{31}{4}+\frac{13}{4}))$

$P=2(\frac{44}{4})=22\ in$

<em>Find the surface area</em>

$SA=2(\frac{403}{16})+22(\frac{31}{8})$

$SA=(\frac{403}{8})+(\frac{682}{8})$

$SA=\frac{1,085}{8}=135.625\ in^{2}$

6 0

3 years ago

Find the value of the question mark

pogonyaev

Answer:

<em>4.88</em>

Step-by-step explanation:

4 0

3 years ago