Find the value of the question mark

8640 divided by40 long division

Tju [1.3M]

The answer is 216.
https://photomath.net/s/YLLqQX

7 0

3 years ago

A company uses this formula to work out the cost, £A, of a taxi ride.

velikii [3]

Answer:

£b = £1.68

A = £44.68

Step-by-step explanation:

Given:

A = 5 + 1.9m + b

Where,

A = total cost

m = number of miles travelled

£b = charge for booking online

£5 = fixed charge

A. Harry

A = £29.48

m = 12 miles

£b = ?

A = 5 + 1.9m + b

29.48 = 5 + 1.9(12) + b

29.48 = 5 + 22.8 + b

29.48 = 27.8 + b

29.48 - 27.8 = b

b = 1.68

£b = £1.68

b) If Sue books online and travels 20 miles, what will be

A = 5 + 1.9m + b

= 5 + 1.9(20) + 1.68

= 5 + 38 + 1.68

= 44.68

A = £44.68

7 0

2 years ago

A graduated cylinder is filled with 36\pi36π36, pi cm^3 3 start superscript, 3, end superscript of liquid. The liquid is poured

lilavasa [31]

By definition, the volume of a cylinder is given by:
V = π * r ^ 2 * h
Where,
r: cylinder radius
h: height
Clearing h we have:
h = (V) / (π * r ^ 2)
Substituting values:
h = (36π) / (π * 3 ^ 2)
h = (36π) / (9π)
h = (36π) / (9π)
h = 4 cm
Answer:
The height of the liquid will be in the new cylinder about:
h = 4 cm

5 0

2 years ago

Read 2 more answers

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago

Find the equation of the line. A line that is perpendicular to the graph of 3x +2y =6 and contains the point (6,-3)

xxMikexx [17]

Answer:

y = 2/3x

Step-by-step explanation:

3x + 2y = 6

2y = 6 - 3x

y = 3 - 3x/2 or y = - 3/2x + 3

- - - - - - - - - - - - - -
Then find the negative reciprocal of the slope of the original line.

y = 2/3x

7 0

2 years ago