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2 years ago

Find the value of the question mark

Mathematics

1 answer:

pogonyaev2 years ago

4 0

Answer:

Step-by-step explanation:

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What is the difference between the 5th multiple of 7 and 3rd multiple of 2 ?

lesya692 [45]

Answer:

<h3>5th Multiple of 7 = 35</h3><h3>3rd Multiple of 2 = 6</h3><h2>The Difference</h2>

=> 35-6

4 0

2 years ago

Can someone please answer letter F ? It applies to the question 4 and the graph on the right , it’s not long .

kherson [118]

F(x)=2x
I would write that since x represents the weeks and we know that she watches two movies a week

6 0

2 years ago

Review the steps of the proof of the identity

astraxan [27]

Answer:

step 2

and then step 3 : the error neutralized the error of step 2

Step-by-step explanation:

sin(a + b) = sin(a)cos(b) + cos(a)sin(b)

and because

sin(-b) = -sin(b)

cos(-b) = cos(b)

we have

sin(a - b) = sin(a)cos(-b) + cos(a)sin(-b) =

= sin(a)cos(b) - cos(a)sin(b)

3pi/2 = 270° or -90°.

sin(3pi/2) = sin(270) = sin(-90) = -1

that means, it is the full radius straight down from the center of the circle.

cos(3pi/2) = cos(270) = cos(-90) = cos(90) = 0

so, step 1 is correct :

sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2) =

= sin(A)×0 - cos(A)×(-1) (correct step 2)

but as we see, the provided step 2 is incorrect.

it should have been the indicated

sin(A)×0 - cos(A)×(-1)

and NOT the provided

sin(A)×0 + cos(A)×(-1)

step 3 based on the erroneous step 2 should then have been

sin(A)×0 - (1)cos(A)

but instead another error with the sign was made that neutralized the error of step 2 and we got after this second mistake by pure chance the overall correct step 3

sin(A)×0 + (1)cos(A)

so, again, the first error was made in step 2.

but technically, there was also a consecutive error made in step 3 to bring everything back to the correct approach.

4 0

2 years ago

PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS

Reil [10]

Given

$x+1 = \sqrt{7x+15}$

We have to set the restraint

$x+1\geq 0 \iff x \geq -1$

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

$(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0$

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

$x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}$

So, we have to impose

$x-7\geq 0 \iff x \geq 7$

Squaring both sides, we have

$(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0$

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0

3 years ago

Alex needs 36 boxes in the carton above.

olganol [36]

Answer:

1 stack of 36

Step-by-step explanation:

First find how much one carton can hold

length is 45

width is 20

height is 40

40 * 20 * 45 = 36,000

Then find how much volume each box has

length is 20

width is 10

height is 5

5 * 10 * 20 = 1000

so each box is 1000 volume

1 stack of 36 is good

7 0

3 years ago