44
The pattern is +1,+1,x2
Answer:

Step-by-step explanation:
observe
||a–b+c|| = ||a+b+c||
(a-b+c)² = (a+b+c)²
(a+b+c)² – (a-b+c)² = 0
((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0
(2a+2c)(2b) = 0
(a+c)b = 0
a•b + c•b = 0
||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0

Hi there!
We can find the perimeter of a rectangle by using the following formula:
perimeter = 2 × width + 2 × length
In the question, we are given the following data: the length of the rectangle is 12 in and the perimeter is 56. Let's substitute this into our formula!
56 = 2 × width + 2 × 12
Multiply first.
56 = 2 × width + 24
Now subtract 24 from both sides.
32 = 2 × width
And finally, to find the width of the rectangle, divide both sides of the equation by 2.
16 = width
(we can eventually switch sides in the equation).
width = 16
~ Hope this helps you!