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lara31 [8.8K]
3 years ago
6

Robert has to make monthly car payments of $ 210​

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

$7 per day

Step-by-step explanation:

not sure if there is more but... If he has to pay $210 in a month he has to pay $7 per day.

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Show that f(x)=(x-2)^3+8 is one to one algebraically
Lelu [443]
What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other

(a-2)^3+8   = a^3-8+8 = a^3

                                             =            a^3 = b^3 square root both side = a=b
 <span>(b-2)^3+8  = b^3-8+8 = b^3


Thus it is 1:1.</span>
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What expression is equivalent to (2x-1)(x-3)?
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Hey dude,

Here we go,

(2x - 1)(x - 3) \\  = 2 {x}^{2}  - 6x - x + 6 \\  = 2 {x}^{2}  - 7x + 6
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3 years ago
(x+7)/(x^2-49) find the domain. show work
harina [27]
\large\begin{array}{l} \textsf{Find the domain of}\\\\ \mathsf{f(x)=\dfrac{x+7}{x^2-49}}\\\\ \mathsf{f(x)=\dfrac{x+7}{x^2-7^2}}\\\\\\ \textsf{Factor out the denominator using special products:}\\\\ \textsf{(a difference of squares)}\\\\ \mathsf{f(x)=\dfrac{x+7}{(x+7)(x-7)}} \end{array}


\large\begin{array}{l} \textsf{Restrictions for the domain:}\\\\ \bullet~~\textsf{Denominators must not be zero:}\\\\ \mathsf{(x+7)(x-7)\ne 0}\\\\ \begin{array}{rcl} \mathsf{x+7\ne 0}&~\textsf{ and }~&\mathsf{x-7\ne 0}\\\\ \mathsf{x\ne -7}&~\textsf{ and }~&\mathsf{x\ne 7} \end{array} \end{array}


\large\begin{array}{l} \textsf{Therefore, the domain of f is}\\\\ \mathsf{D_f=\{x\in\mathbb{R}:~~x\ne -7~~and~~x\ne 7\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_f=\mathbb{R}\setminus\{-7,\,7\}}\\\\\\ \textsf{or using the interval notation}\\\\ \mathsf{D_f=\left]-\infty,\,-7\right[\,\cup\,\left]7,\,+\infty\right[.} \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2155752


\large\textsf{I hope it helps. :-)}



Tags: <em>function domain real rational factorizing special product interval</em>

</span>
7 0
3 years ago
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MakcuM [25]

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Hopefully this helps, and please consider marking branliest.

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Step-by-step explanation:

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