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Archy [21]
3 years ago
6

Give me the best answer

Mathematics
1 answer:
Nadya [2.5K]3 years ago
7 0
After rewriting all sets of data from smaller to greater, I found that the last series is the one that is represented by the plot box:

79,86,88,88,92,98,100,106,115,136

Why? Because The median is 95 (like the box)

because the outliers are >  115  (up to 136)
 because their is no outlier on the left by the mini value of 79
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1. A jeepney driver claims that his average monthly income is Php 3000.00 with a standard deviation of Php 300.00. A sample of 3
nydimaria [60]

Answer:

Kindly check explanation

Step-by-step explanation:

The hypothesis :

H0 : μ = 3000

H0 : μ ≠ 3000

The test statistic :

(xbar - μ) ÷ (s/√(n))

xbar = 3500

μ = 3000

σ = 300

n = 30

(3500 - 3000) ÷ (350/√(30))

Test statistic = 7.824

Df = 30 - 1 = 29

Tcritical at 0.01 = 2.462

Test statistic > critical value ; we reject H0 ; and concluded that there is significant evidence that

μ ≠ 3000

7 0
3 years ago
Question 7(Multiple Choice Worth 75 points) Which of the following is true of all minerals? Made of many different elements Come
algol [13]
The true statement is that minerals come from the ground as crystals. Hope this helps!
4 0
3 years ago
MIDNIGHT HOMEWORK -1 5/6 divided by (-3 1/3 plz help me
MA_775_DIABLO [31]

Answer:

11/20

Step-by-step explanation:

I turned them in to improper fractions, divided, then simplified

6 0
3 years ago
Estimate the sum by first rounding each
sukhopar [10]
5 3/8 rounds to 5,
4 7/10 rounds to 5
Your estimated sum is 10
5 0
3 years ago
Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64

c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

3 0
4 years ago
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