3x- 4y=10
10÷1=10
Therefore y is equal to 10
Difference between the mean of the data, including the outlier and excluding the outlier is;
B: 0.93
<h3>Mean average</h3>
Her time in minutes for the given months are;
- January = 41.55 minutes
- July = 36. 38 minutes
- Feb = 42.51 minutes
- Aug = 38.48 minutes
- Mar = 43. 01 minutes
- Sept = 41.87 minutes
- Apr = 39. 76 minutes
- Oct = 51.32 minutes
- May = 37. 32 minutes
- Nov = 42.59 minutes
- June = 35.28 minutes
- Dec = 43.71 minutes
Looking at all the numbers, they largely range from 36 to 44 which means that the outlier is 51.32
Total number of minutes with outlier = 493.78 minutes
Number of months = 12
Thus;
Mean with outlier = 493.78/12
Mean with outlier = 41.15 minutes
Mean without outlier = (493.78 - 51.32)/(12 - 1)
Mean without outlier = 40.22 minutes
Thus;
Difference in both means = 41.15 - 40.22
Difference = 0.93
Read more about mean average at; brainly.com/question/20118982
Answer:
true
Explanation:
to fix a computer problem you have to know what is wrong with it
Cos(2θ) = cos²θ - sin²θ = (1-sin²θ)-sin²θ = 1-2(7/9)^2 = -17/81
