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mash [69]
2 years ago
10

Pls help with this math problem

Mathematics
1 answer:
valentinak56 [21]2 years ago
7 0
-1.5. -1 1/2. -3/2






yeah so its this i’m 99.98% sure
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Help me get the possible point, no link or virus please.
matrenka [14]

Answer:

k(x) = -40

i(x) = -15

n(x) = 71

d(x) = 17

Step-by-step explanation:

This is exactly the same deal as the most recent question you asked.

"Evaluate each function for x = 8". In other words, this is saying, calculate the result for each function, replace x with 8. So, that means for every function, you are going to replace x with 8.

k(x) = -5x turns into k(x) = -5(8)

Then you just solve, -5(8) = -40

Since I have answered this question similarly, I ask that you go back to the answer and detailed explanation I gave you earlier.

6 0
2 years ago
Solve for x.<br><br><br><br> 80<br> 22<br> 40<br> 12
kari74 [83]
Use the Pythagorean theorem to solve this problem. So, 81+x^2=1681. ( Pythagorean theorem: a^2+b^2=c^2). x^2=1600. x=40.
4 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
You have a gross income of $117,151 and are filing your tax return singly. You claim one exemption and can take a deduction of $
Grace [21]
Answer is $10,825 did that test too (C)
3 0
3 years ago
Read 2 more answers
I need help on number 16 please and thank you ! For brainlest answer
marusya05 [52]
M5 is the same as m1 so it's 75°
6 0
3 years ago
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