Mr. Kugler gave the same geometry test to his 1st and 2nd period classes. The box and whisker plot summarizes the scores of each
class. Which statement is true about the data? A) The mean of 1st Period is higher than the mean of 2nd Period. B) The median of 1st Period is greater than the median of 2nd Period. C) The lowest score made on the test for both classes is 70. D) The median of 2nd Period is greater then the median of 1st Period.
2 answers:
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Answer:
a) The probability that at least 5 ties are too tight is P=0.0432.
b) The probability that at most 12 ties are too tight is P=1.
Step-by-step explanation:
In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.
a) We can express the probability that at least 5 ties are too tight as:
The probability that at least 5 ties are too tight is P=0.0432.
a) We can express the probability that at most 12 ties are too tight as:
The probability that at most 12 ties are too tight is P=1.
Given:
One linear function represented by the table.
Another linear function represented by the graph.
To find:
The greater unit rate and greater y-intercept.
Solution:
Formula for slope (unit rate):
From the given table it is clear that the linear function passes through (0,5) and (5,15). The function intersect the y-axis at (0,15), so the y-intercept is 15.
So, the unit rate of first function is 2.
From the given graph it is clear that the linear function passes through (0,6) and (-4,0). The function intersect the y-axis at (0,6), so the y-intercept is 6.
So, the unit rate of first function is .
Now,
And,
Therefore, the greater unit rate of the two functions is 2. The greater y-intercept of the two functions is 15.