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Umnica [9.8K]
3 years ago
15

A liquid has a low boiling point and is a poor conductor of electricity. The liquid could be which of the following? select all

that apply
a. H2O
b. CaCl2
c. CH4
d. FePO4
Chemistry
1 answer:
Black_prince [1.1K]3 years ago
8 0

The liquid which has a low boiling point and is a poor conductor of electricity is Methane (CH4).

<h3>What is covalent Compounds?</h3>

Covalent Compounds are compounds with low boiling point and are poor conductors of heat and electricity. Covalent compounds have strong intra-molecular bonds. This is because the atoms within the covalent molecules are very tightly held together.

Methane (CH4) is a liquid that has a low boiling point and is a poor conductor of electricity.

Read more on Covalent Compounds:

brainly.com/question/11651796

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Calculate the χacetone and χcyclohexane in the vapor above the solution. p°acetone = 229.5 torr and p°cyclohexane = 97.6 torr.
Ulleksa [173]
First calculate the mole fraction of each substance:
Acetone: 2.88 mol ÷ (2.88 mol + 1.45 mol) = 0.665
Cyclohexane: 1.45 ÷ (2.88 mol + 1.45 mol) = 0.335
Raoult's Law: P(total) = P(acetone) · χ(acetone)  + P(cyclohexane) · χ(cyclohexane).
P(total) = 229.5 torr · 0.665 + 97.6 torr · 0.335
P(total) = 185.3 torr
χ for acetone: 229.5 torr · 0.665 ÷ 185.3 torr = 0.823 
χ for cyclohexane:  97.6 torr · 0.335 ÷ 185.3 torr = 0.177
7 0
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<em>Answer,</em>

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This is the process that cells reproduce and replace old or damaged cells.
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The answer is A. mitosis
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Complete the equation determine if there are precipitates write the balanced ionic and net ionic equations. If there is no preci
alukav5142 [94]

You may find bellow the balanced chemical equations.

Explanation:

Molecular equations:

3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)

2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)

Ionic equations:

3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)

2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)

To get the net ionic equation we remove the spectator ions:

3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s)

2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)

Learn more about:

net ionic equations

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