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4 years ago

How many distinct dichlorination products can result when isobutane is subjected to free radical chlorination?

Chemistry

1 answer:

Elenna [48]4 years ago

4 0

Answer:

c. 3

Explanation:

Dicholorination of tertiary alkane ( i.e. isobutane) is a halogenation reaction which makes it possible to replace the alkyl functional group with halogenated chlorine.

When Isobutane is subjected to free radicals chlorination, three distinct dichlorination can be formed.

The mechanism of the formation of these products can be seen in the image attached below.

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Bob is cleaning his dishwasher with white vinegar by putting a bowl of this ____________ mixture in the top of an empty dishwash

trasher [3.6K]

Hi JavonEtuff2,

Answer - B. Homogeneous

Store bought vinergars are typically have been filtered which makes it homogeneous. In the question it states white vinegar which has been distilled and pure mixture of water and acetic acid.

5 0

4 years ago

suppose that during the icy hot lab that 65 kj of energy were transferred to 450 g of water at 20 C. What would have been the fi

balandron [24]

Answer:

The final temperature of water is 54.5 °C.

Explanation:

Given data:

Energy transferred = 65 Kj

Mass of water = 450 g

Initial temperature = T1 = 20 °C

Final temperature= T2 = ?

Solution:

First of all we will convert the heat in Kj to joule.

1 Kj = 1000 j

65× 1000 = 65000 j

specific heat of water is 4.186 J /g. °C

Formula:

q = m × c × ΔT

ΔT = T2 - T1

Now we will put the values in Formula.

65000 j = 450 g × 4.186 J /g. °C × (T2 - 20°C )

65000 j = 1883.7 j /°C × (T2 - 20°C )

65000 j/ 1883.7 j /°C = T2 - 20°C

34.51 °C = T2 - 20°C

34.51 °C + 20 °C = T2

T2 = 54.5 °C

5 0

4 years ago

FREE BRAINIEST WHO WANTS IT?!!!

tia_tia [17]

Ngl, I really want it! But how do I know you're not scamming?

8 0

3 years ago

Read 2 more answers

a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc

ladessa [460]

Answer:

The molarity of the solution is 1.1 $\frac{moles}{liter}$

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case

number of moles of solute= 0.564 moles
volume= 0.510 L

Replacing:

$molarity=\frac{0.564 moles}{0.510 L}$

Solving:

molarity= 1.1 $\frac{moles}{liter}$

The molarity of the solution is 1.1 $\frac{moles}{liter}$

4 0

3 years ago

Consider the reaction Ca(OH)2(s)→CaO(s)+H2O(l) with enthalpy of reaction ΔHrxn∘=65.2kJ/mol What is the enthalpy of formation of

Ganezh [65]

Answer:

ΔH °fCaO= -655.09 KJ/mol = ΔH °fCaO

Explanation:

ΔH °(reaction)a=ΔH °f(product)-ΔH °f(reactant)

where,

ΔH °f(product)=is the standard heat of formation of products

-ΔH °f(reactant)=is the standard heat of formation of reactants

The standard heat of formation of H 2 O ( l ) is − 285.8 k J / m o l .

The standard heat of formation of Ca(OH )2 is − 986.09 k J / m o l .

For the given reaction, the standard enthalpy change is calculated by the expression shown below.

ΔH °(reaction)a=ΔH °f(CaO+H2O)-ΔH °f(Ca(OH)₂

65.2 = ΔH °fCaO+( -265.8) -(-986.09)

= ΔH °fCaO-265.8+986.09

65.2 = ΔH °fCaO+ 720.29

65.2-720.29 = ΔH °fCaO

-655.09 KJ/mol == ΔH °fCaO

3 0

3 years ago