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3 years ago

How many distinct dichlorination products can result when isobutane is subjected to free radical chlorination?

Chemistry

1 answer:

Elenna [48]3 years ago

4 0

Answer:

c. 3

Explanation:

Dicholorination of tertiary alkane ( i.e. isobutane) is a halogenation reaction which makes it possible to replace the alkyl functional group with halogenated chlorine.

When Isobutane is subjected to free radicals chlorination, three distinct dichlorination can be formed.

The mechanism of the formation of these products can be seen in the image attached below.

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Ionic bonds form between which two types of elements?

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Answer:

Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl.

Explanation:

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2 years ago

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Aluminum can react with oxygen gas to produce aluminum oxide (Al2O3). What type of reaction is this?

Pachacha [2.7K]

It's Synthesis, single replacement is incorrect.

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3 years ago

Having energy in the reactant lead to an exothermic reaction.<br>true<br>false

Ostrovityanka [42]

Answer:

false

Explanation:

first of all;-energy lead to an indotermic reaction.

indotermic is a reaction that absorbs energy \

*it has positive enthalpy of reaction

*Heat content of product is greater than that of reactant

*Heat is added to reactant side

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3 years ago

A sample of gas with an initial volume of 28.4 Liters at a pressure of 725 mmHg and a temperature of 305 K is compressed to a vo

Lerok [7]

Answer:

The final pressure is 2.25 atm or 1710 mm Hg

Explanation:

Step 1: Data given

The initial volume = 28.4 L

The initial pressure = 725 mm Hg ( = 725/760 atm) = 0.953947 atm

The initial temperature = 305 K

The new volume is 14.8 L

The new temperature = 375 K

Step 2: Calculate the new pressure

(P1*V1)/T1 = (P2*V2)/T2

⇒ with P1 = the initial pressure = 725 mmHg = 0.953947 atm

⇒ with V1 = the initial volume = 28.4 L

⇒ with T1 = The initial temperature = 305 K

⇒ with P2 = the new pressure = TO BE DETERMINED

⇒ with V2 = the new volume = 14.8 L

⇒ with T2 = the new temperature = 375 K

(0.953947 * 28.4)/305 = (P2 * 14.8)/375

P2 = 2.25 atm = 1710 mm Hg

The final pressure is 2.25 atm or 1710 mm Hg

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3 years ago

What is the democritus findings?

Volgvan

nvm

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3 years ago