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Answer:
The reaction would take place with racemization.
Explanation:
The compound (R)-3-bromo 3-methylhexane contains has the leaving group attached to a tertiary carbon atom. When the leaving group is attached to a tertiary carbon atom, the compound undergoes nucleophilic substitution via SN1 mechanism. This mechanism involves the formation of a planar carbocation intermediate. The nucleophile may attack this intermediate from either faces, leading to racemization of the product.
Answer:
6.022 ×10(index 23) / 7.5 = 0.8293 ×10(index 23)
Explanation:
molar mass of C = 12gmol
therefore in 12g of C there is one mole or an amount of 6.022 ×10(index 23)
∴12g/6.02210(index 23) ×1.6g
Answer:

Explanation:
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In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

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