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lesya692 [45]
2 years ago
7

What is the variance of the data? 0.0625 0.25 0.5 1.5

SAT
1 answer:
dybincka [34]2 years ago
7 0

The variance of the dataset is the square of their standard deviation

The variance of the dataset is 0.307

<h3>How to determine the variance?</h3>

The dataset is given as;

0.0625 0.25 0.5 1.5

Calculate the mean using:

μ = Sum/Count

So, we have:

μ = (0.0625 + 0.25 + 0.5 + 1.5)/4

Evaluate

μ = 0.578125

The variance is then calculated using:

\sigma^2 = \frac{\sum(x - \mu)^2}{n}

So, we have:

\sigma^2 = [(0.0625 - 0.578125)^2 + (0.25 - 0.5781250^2 + (0.5 - 0.578125)^2 + (1.5 - 0.578125)^2]/4

Evaluate

\sigma^2 = 1.2294921875/4

Divide

\sigma^2 = 0.30737304687

Approximate

\sigma^2 = 0.307

Hence, the variance of the dataset is 0.307

Read more about variance at:

brainly.com/question/15858152

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the following data give the hours spent studying per week by nine students. 12, 16, 7, 22, 11, 18, 7, 25, 16. (a) find the mean,
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Mean: 14.8888888889

Median: 16

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Range: 18

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who was a painter, sculptor, architect, engineer, scientist, philosopher, and a visionary? this person was commissioned by the d
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2 years ago
The base of s is the region enclosed by the parabola y = 3 − 2x2 and the x−axis. Cross-sections perpendicular to the y−axis are
Vlad [161]

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<h3>Integral Volume of a Solid</h3>

The length of each cross-section is determined by the horizontal distance (parallel to the x-axis) from one end of the parabola to the other.

Thus;

y = 3 - 2x²

Making x the subject gives us;

x = ±√[(3 - y)/2]

Thus;

The horizontal distance is;

√[(3 - y)/2] - (-√[(3 - y)/2])

⇒ 2√[(3 - y)/2]

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