<span>A polynomial with the given zeros can be represented as
f(x) = (x-1)(x-2)(x+2)(x+3).
Note that if you set f(x) = 0, then 1,2,-2, and -3 certainly are the solutions. From here, we simply multiply/expand out the polynomial. We can do this in a variety of ways, one of which is taking the left two and right two products separately. We have
(x-1)(x-2) = x^2 - 3x + 2
and
(x+2)(x+3) = x^2 + 5x + 6.
This gives that
f(x) = (x^2 - 3x + 2) (x^2 + 5x + 6).
Expanding this expression out then gives us our answer as f(x) = x^4 + 2x^3 - 7x^2 - 8x + 12
or answer choice B.</span>
Hello : note : <span> <span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r² </span></span>in this exercice : a =0 b = 0 r =8 <span>the equation of the circle is : x²+y² = 64</span>
