Step-by-step explanation:
This can be put into fractions like this
Say x is the length of the missing dimension
8.5/11 = 10.5/x
Because the 2 drawings are SIMILAR, the ratio of their side lengths has to also be the same
8.5 ÷ 10.5 = 0.8095
11 × 0.8095 = 8.9047
Roung the answer to the nearest tenth
x = 8.9 in
triangle TUV is congruent to triangle TBA
by SAS congruency
hope it helps...!!!!
Answer:
- As the slopes of both lines 'm' and 'n' are the same.
Therefore, we conclude that the equation x-2y=4 represents the equation of the line 'n' if lines m and n are parallel to each other.
Step-by-step explanation:
We know that the slope-intercept of line equation is
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Where m is the slope and b is the y-intercept
Given the equation of the line m
y = 1/2x - 4
comparing with the slope-intercept form of the line equation
y = mx + b
Therefore,
The slope of line 'm' will be = 1/2
We know that parallel lines have the 'same slopes, thus the slope of the line 'n' must be also the same i.e. 1/2
Checking the equation of the line 'n'
![x-2y=4](https://tex.z-dn.net/?f=x-2y%3D4)
solving for y to writing the equation in the slope-intercept form and determining the slope
![x-2y=4](https://tex.z-dn.net/?f=x-2y%3D4)
Add -x to both sides.
![x - 2y + (-x) = 4+(-x)](https://tex.z-dn.net/?f=x%20-%202y%20%2B%20%28-x%29%20%3D%204%2B%28-x%29)
![-2y = 4 - x](https://tex.z-dn.net/?f=-2y%20%3D%204%20-%20x)
Divide both sides by -2
![\frac{-2y}{-2}=\frac{-x+4}{-2}](https://tex.z-dn.net/?f=%5Cfrac%7B-2y%7D%7B-2%7D%3D%5Cfrac%7B-x%2B4%7D%7B-2%7D)
![y=\frac{1}{2}x-2](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx-2)
comparing ith the slope-intercept form of the line equation
Thus, the slope of the line 'n' will be: 1/2
- As the slopes of both lines 'm' and 'n' are the same.
Therefore, we conclude that the equation x-2y=4 represents the equation of the line 'n' if lines m and n are parallel to each other.
Answer: 54:150
Step-by-step explanation:
The ratio of bass to catfish in a pond can be written as 54:150
Answer:
Step-by-step explanation:
A direct variation equation is of the form
y = kx,
where, in words, it reads "y varies directly with x" or "y varies directly as x". In order to use this as a model, we have to have enough information to solve for k, the constant of variation. The constant of variation is kind of like the slope in a straight line. It rises or falls at a steady level; it is the rate of change.
We have that a vet gives a dose of three-fifths mg to a 30 pound dog. If the dose varies directly with the weight of the dog, then our equation is
d = kw and we need to find k in order to have the model for dosing the animals.
![\frac{3}{5} =k(30)](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%20%3Dk%2830%29)
Divide both sides by 1/30 to get k alone.
and
![k=\frac{1}{50}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7B50%7D)
Our model then is
![d=\frac{1}{50}w](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%7D%7B50%7Dw)
This means that for every pound of weight, the dog will get one-fiftieth of a mg of medicine.