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katrin [286]
2 years ago
5

Use numerals instead of words. If necessary, use / for the fraction bar

Mathematics
1 answer:
earnstyle [38]2 years ago
6 0
DE should be 4.5 i think
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Classify the following triangle. Check all that apply
kramer
D and E. If I remember right that should be the answer.
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3 years ago
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rosa is saving money for a trip. she has already saved $250 and plans to save $40 per week. this situation can be represented by
malfutka [58]

Rosa has saved $490 in 6 weeks.

To find the answer to this, simply plug the number of weeks in for the value of x and solve.

f(x) = 250 + 40x

f(6) = 250 + 40(6)

f(6) = 250 + 240

f(6) = 490

5 0
3 years ago
How do you do the shortcut method
Gala2k [10]
<span>Add both the result (1×3 + 1×3) = 6 and write down to the left of 9 (result ofstep 1).

</span>
8 0
3 years ago
What is the first step when rewriting y = 3x2 9x – 18 in the form y = a(x – h)2 k?
stiks02 [169]
A quadratic equation has the general form of: <span>

y=ax² + bx + c

It can be converted to the vertex form in order to determine the vertex of the parabola. It has the standard form of:

y = a(x+h)² - k

This can be done by completing a square. The steps are as follows:

</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18 
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
3 0
3 years ago
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Solve the system of linear equations.
sweet-ann [11.9K]

Answer:

  • dependent system
  • x = 2 -a
  • y = 1 +a
  • z = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

  x + y = 3 . . . . . . divide by 9 [eq4]

Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

  x + y = 3 . . . . . . divide by 18 [eq5]

Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

<em>Check</em>

First equation:

  3(2-a) -3(a+1) +6a = 3

  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

6 0
2 years ago
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