Given:
Christopher scores 2 goals in a soccer game.
His goal total can vary from the average by 1 goal.
To find:
The absolute value equation can be used to calculate Christopher's maximum and minimum goals per game.
Solution:
Let Christopher scores x goals in a soccer game.
Then difference between actual goals and average goals is x-2.
His goal total can vary from the average by 1 goal.
Maximum number of goals = 2+1 = 3
Minimum number of goals = 2-1 = 1
It means, the difference between actual goals and average goals is either -1 and 1.
...(1)
...(2)
Using (1) and (2),we get
Therefore, the correct option is C.
You have to use implicit derivative
dy / dx = y'
xy^3+y=3x
y^3 + 3xy^2 y' + y' = 3
[3xy^2 + 1) y'= 3 - y^3
3 - y^3
y' = ----------------- <-----------answer
3xy^2 + 1
X-6y=6 slope: 1/6 y-intercept (0,1)
X= 0,6 y= -1, 0
X+3y+12=0 slope: 1/3
Y-intercept (0,4) x= -12, 0 Y= 0,4
8a-9b= 9/8 slope (0 ,7/8) x= -1,1 Y= -1/4,2
3a+b=7 1/3 (0,7/3) x= 4,7 Y=1,0
The first four-term of the sequence is found by the given equation 
is given as 144, 36, 9, and 9/4.
<h3>What is a sequence?</h3>
A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.
The given equation will be
And
For n = 4, we have
For n = 3, we have
For n = 2, we have
More about the sequence link is given below.
brainly.com/question/21961097
Answer:
C. x+y = 1 and -x-y = -1
Step-by-step explanation:
Remember that if a system of equations has an infinite number of solutions, then the resulting equation from using the first step of the elimination method would have no variables and would be true.
1) Let's try canceling out the equations in option C, x+y =-1 and -x-y =-1. Add the two equations together. (Work shown in attached picture.)
2) All of the terms cancel out with each other, leaving only a true statement of 0 = 0. Thus, option C is the answer.
