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lukranit [14]
3 years ago
12

Please help me someone ASAPP!

Mathematics
1 answer:
Aloiza [94]3 years ago
3 0

Answer:

Look at the expalnation picture attatched!!!

Step-by-step explanation:

a)plot (6,-1), (0,-4), (-4,-6) then draw teh line connecting all of these points ( Graph with black line is how it shoudl look)

b) plot (-2,0), (0,6), (-4,-6) then draw the line that connects all of these points (picture with red line graph is how this problem should look).

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Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.
Naya [18.7K]
It's a geometric sequence.

4,-12,36,... \\ \\
a_1=4 \\
r=\frac{a_2}{a_1}=\frac{-12}{4}=-3 \\ \\
a_n=a_1 \times r^{n-1} \\
a_n=4 \times (-3)^{n-1} \\
a_n=4 \times (-3)^{-1} \times (-3)^n \\
a_n=4 \times (-\frac{1}{3}) \times (-3)^n \\
a_n=-\frac{4}{3}(-3)^n

It's the sum for term 4 through term 15.

 \boxed{ \sum\limits_{n=4}^{15} (\frac{4}{3}(-3)^n)}
8 0
3 years ago
What is 3 In3-In9 expressed as a single natural logarithim
Alexandra [31]

3 \ln 3 - \ln 9 = 3 \ln 3 - \ln 3 ^2 = 3 \ln 3 - 2 \ln 3 = \ln 3

Answer: \ln 3

7 0
3 years ago
Read 2 more answers
The given two-parameter family is a solution of the indicated differential equation on the interval
mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)

Replace C_1 = 0 we have

y'(\pi) = -C_2e^\pi = 0

if and only if C_2 =0

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0
3 years ago
Explain how they are different AND the same
True [87]

Proportional and linear functions are almost identical in form. The only difference is the addition of the “b” constant to the linear function. Indeed, a proportional relationship is just a linear relationship where b = 0, or to put it another way, where the line passes through the origin

3 0
3 years ago
You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 35 bacteria reveals a sampl
pickupchik [31]

Answer: Sample size would be 296.

Step-by-step explanation:

Since we have given that

Standard deviation = 4.8 hours

Margin of error = 0.65 hours

At 98% level of confidence, z = 2.33

So, It becomes,

0.65=z\times \dfrac{\sigma}{\sqrt{n}}\\\\0.65=2.33\times \dfrac{4.8}{\sqrt{n}}\\\\\dfrac{2.33\times 4.8}{0.65}=\sqrt{n}\\\\n=(\dfrac{11.184}{0.65})^2\\\\n=17.206^2\\\\n=296.051

Hence, sample size would be 296.

7 0
3 years ago
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