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larisa [96]
3 years ago
5

Answer 12 plzzzz‼️‼️ asap!

Mathematics
2 answers:
Leto [7]3 years ago
7 0
Create equal fractions to find the number of hours he used the health club for.

2/13=x/29.25

Then, simplify so that x is by itself.

(29.25x2)/13 = x
x= 58.5/13
x=4.5 hours
guapka [62]3 years ago
7 0
13/2 = 6.5
They charge $6.50 per hour
29.25/6.50 = 2925/650 = 4.5
He was in the health club for ~ 4.5 hours

hope this helps
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Harvard University accepts 6 students for every 100 applicants. How many students will be accepted if 850 applicants apply for a
patriot [66]

Answer:

51 accepted

Step-by-step explanation:

Well, if 6 are accepted out of 100, that's 6% or 0.06. To find how many are accepted out of 850, multiply 850 by 0.06.

4 0
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So 6+3 is 9 right? So let's just say it's 9:37 with a 45 min ride. 60 minutes are in a hour. 60 - 37 = 23. We have 23 minutes left until 10:00. 45- 23 = 22. Therefore it'd be 10:22 p.m.
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Your friend earns $10.50 per hour this is 125% of her hourly wage last year how much did your friend make last year
NNADVOKAT [17]
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2.10*4=8.40
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3 0
3 years ago
....................
Viefleur [7K]

Answer:

<em>C:</em><em> </em><em>is</em><em> </em><em>co</em><em>rrect</em><em> answer</em>

<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>

<em>3 \times  {10}^{5}</em>

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A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

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Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

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3 years ago
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