All categories

3 years ago

You attend a working dinner with four other colleagues. Since alcohol

Mathematics

1 answer:

murzikaleks [220]3 years ago

4 0

Using proportions, it is found that the amount owed for each bill are given as follows:

$31.33 for food $9.90 for alcohol.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount.

In this problem, each of the bills are split equally among the five people, hence the fraction is 1/5.

Thus:

1/5 x 156.65 = $31.33

1/5 x 49.50 = $9.90.

Hence the amount owed for each bill are given as follows:

$31.33 for food $9.90 for alcohol.

More can be learned about proportions at brainly.com/question/24372153

You might be interested in

Rewrite the equation in standard form by expanding it. <br> y= 3 (x+2)^2 - 4

morpeh [17]

Answer:

y = 3x^2 + 12x + 8

Step-by-step explanation:

To rewrite in standard from by expanding the equation using the distributive property.

y= 3 (x+2)^2 - 4

y = 3(x^2 + 4x + 4) - 4

y = 3x^2 + 12x + 12 - 4

y = 3x^2 + 12x + 8

4 0

3 years ago

PLEASE HELP

GREYUIT [131]

Answer:

Step-by-step explanation:

Polygon A translated 5 blocks right.

4 0

3 years ago

The proprietor of a boutique in New York wanted to determine the average age of his customers. A random sample of 25 customers r

jolli1 [7]

Answer:

$28-2.064\frac{10}{\sqrt{25}}=23.872$

$28+2.064\frac{10}{\sqrt{25}}=32.128$

So on this case the 95% confidence interval would be given by (23.9;32.1)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=28$ represent the sample mean

$\mu$ population mean (variable of interest)

s=10 represent the sample standard deviation

n=25 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=25-1=24$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,24)".And we see that $t_{\alpha/2}=2.064$