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3 years ago

What two numbers have a GCF of 5 and a LCM of 50

Mathematics

1 answer:

Komok [63]3 years ago

5 0

Answer:

10 and 5

Step-by-step explanation:

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Create the equation of a parabola using the function h(t) = -16t2 + h0 where h(t) is the height (in feet) of an object thrown fr

butalik [34]

H(t)=-16t²+500
0=-16t²+500
16t²=500
t²=31.25
t=5.9 seconds before the object hits the ground
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3 years ago

Given m||n, find the value of x

fenix001 [56]

X is equal to 2. you can set them equal to each other because they are corresponding angles, which means they are congruent.

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2 years ago

Read 2 more answers

Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from

Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that $P = 3000, r = 0.16, n = 1$

$A(t) = P(1 + \frac{r}{n})^{nt}$

$A(t) = 3000(1 + \frac{0.16}{1})^{t}$

$A(t) = 3000(1.16)^{t}$

(a) Find the amount in the account at the end of 1 year.

This is A(1).

$A(t) = 3000(1.16)^{t}$

$A(1) = 3000(1.16)^{1} = 3480$

(b) Find the amount in the account at the end of 2 years.

This is A(2).

$A(2) = 3000(1.16)^{2} = 4036.8$

4 0

3 years ago

Need a little help with one please

Pani-rosa [81]

Answer:

That would be the side-side-side (SSS) postulate, which states that if all the sides of a triangle are in a fixed ratio to all the corresponding sides of another triangle, then the two triangles are said to be congruent.

Step-by-step explanation:

Looking at triangles ABC and DEF, we notice that:

$\frac{AB}{DE} = \frac{AC}{DF}=\frac{BC}{EF}$