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Lera25 [3.4K]
2 years ago
14

How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2. X 2 6x – 4y = –10 one

solution: (–0. 6, –1. 6) one solution: (–0. 6, 1. 6) no solution infinite number of solutions.
Mathematics
1 answer:
nordsb [41]2 years ago
3 0

The system of equations provides a unique solution(one solution) at (-0.6, 1.6).

<h2>Given to us,</h2>
  1. y=\dfrac{2}{3}x+2
  2. 6x-4y=-10

<h3>Equation 2</h3>

As we already have the value of y from equation 1, substitute its value in equation 2,

6x-4y=-10

6x-4(\dfrac{2}{3}x+2)=-10

6x-\dfrac{8}{3}x-8=-10

\dfrac{6x}{1}-\dfrac{8}{3}x=-10+8

\dfrac{6x\times 3}{1\times 3}-\dfrac{8}{3}x=-2

\dfrac{18x-8x}{3}=-2

10x=-6\\

x=\dfrac{-6}{10} \\\\x=-0.6

<h3>Equation 1,</h3>

y=\dfrac{2}{3}x+2

substitute the value of x in equation 1,

y=\dfrac{2}{3}(\dfrac{-6}{10})+2\\\\y = \dfrac{-2}{5}+2\\\\y= \dfrac{-2+10}{5}\\\\y = \dfrac{8}{5}\\\\y=1.6

As we can see the system of equations provides a unique solution(one solution) at (-0.6, 1.6).

Learn more about the system of equations:

brainly.com/question/12895249

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