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SashulF [63]
2 years ago
13

HELP HELP I NEED HELP​

Mathematics
2 answers:
Papessa [141]2 years ago
8 0

Answer:

<u>a. 1385.44 ft²</u>

Step-by-step explanation:

<u>Area of a circle</u>

  • πr²

<u>Given</u>

  • r = 21 ft

<u>Solving</u>

  • 22/7 x 21 x 21
  • 22 x 3 x 21
  • 66 x 21
  • 1386 ft²
  • Option A is the closest answer
zheka24 [161]2 years ago
7 0

\color{red}{ \tt{Given : }}

\textbf{ radius = 21 ft }

\color{red}{ \tt{Solution : }}

\textbf{Area of circle = πr²}

\bold{ =   \frac{22}{\cancel{7}}  × \cancel{21} × 21 }

\textbf{= 22 × 3 × 21 }

\textbf{= 1386 ft²}

{\boxed{{area \:  =  1386 ft²}}}

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Find the point that partitions CD in the ratio 1:2 c(-1,7) and d(5, 1)
Amiraneli [1.4K]

Coordinates of the point that partitions the line into the given ratio is; (1, 5)

<h3>How to divide a line segment?</h3>

If the ratio dividing a line segment represents a:b, then the formula to divide  the line segment is;

Coordinates = {(bx₁ + ax₂)/(a + b), (by₁ + ay₂)/(a + b)}

From our question, we have the ratio as;

1:2. Thus; a = 1 and b = 2

Our coordinate of CD is; C(-1,7) and D(5, 1)

Thus;

x₁ = -1

x₂ = 5

y₁ = 7

y₂ = 1

Coordinates of the point that partitions the line into the given ratio is;

Coordinate = {(2*-1 + 1*5)/(1 + 2), (2*7 + 1*1)/(1 + 2)}

Coordinate = (3/3, 15/3) = (1, 5)

Read more about Division of Line Segment at; brainly.com/question/17374569

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Find the perimeter of a triangle with the points,
liberstina [14]

Answer:

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3 0
3 years ago
The volume of a cone is 1540cm³. If its radius is 7cm, calculate the height of the cone. (Take pi = 22/7)
Ann [662]

Answer:

h=30

Step-by-step explanation:

Volume of a cone=1540cm^{3}, Radius=7cm.

The height of a cone=h

When we need to find the height of a cone, we can use the formula of the volume of a cone, which is \frac{1}{3} \pi r^{2} h to find the height of a cone.

1540cm^{3} =\frac{1}{3}\pi r^{2}  h

Put the pi value=22/7 and the value of radius which is 7 cm into the formula.

1540cm^{3}=\frac{1}{3}*\frac{22}{7}  7^{2}h

1540cm^{3} =\frac{154}{3}h

Move \frac{154}{3} to another side. 1540 divided by  \frac{154}{3} to calculate what is the value of h, h is the height of a cone. Like this.

\frac{1540cm^{3} }{\frac{154}{3} } =h

30=h

Rearrange the h.

h=30

I hope you will understand my solution and explanation. If you still cannot get the point, you can ask me anytime! Thank you!

4 0
3 years ago
Read 2 more answers
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Llana [10]

Answer:

By substituting the values of A, C, and D the equation modelling the function is;

g(x) = 3·sin(x - π/2) - 4

Step-by-step explanation:

From the given information, we have;

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Given that the horizontal shift left = π/2 units, (from an online source with similar question)

The vertical shift down = 4 units

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Where;

A = The amplitude = The maximum displacement from the rest or equilibrium position = 3

C = The horizontal shift = -π/2 (The negative sign is for the shifting to the left)

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g(x) = 3·sin(x - π/2) - 4

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3 years ago
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It means , out of 30 days ,there are  only 20 days , in which temperature is above 80°F.

⇒Probability that it will be above 80° F for 20 or more days this June

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where, x is the number of extra days after 20 days in month of june, when temperature is above 80°F.

Value of this Probability will be in between

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Now, what Azul wants

 To find the probability that it will be above 80° F for 20 or more days this June.

The Simulation given is

  ⇒There are 30 days in June. If we use a number cube with the numbers 1-6 and assign 1-4 as a temperature above 80° F and 5-6 as a temperature 80° F or below.

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Favorable Outcome={1,2,3,4}=Temperature above 80° F

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        =\frac{4}{6}\\\\=\frac{2}{3}

⇒Probability of getting number {5,6} on the number cube when rolled once, that is Temperature 80° F or below

        =\frac{2}{6}\\\\=\frac{1}{3}

This is Incorrect Simulation, as there are chances that , there can be more than 20 days out of 30 days when Temperature goes above 80° F.But Here we have got Probability of temperature being above 80° F for 20 days only, not more than 20 days, which is =\frac{2}{3}

Not,a number

    \frac{2}{3}< \text{Probability} \leq 1.    

4 0
4 years ago
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