16, 18, 23, 25, 26, 34, 37, 37, 40, 41, 46
37 is the upper quartile value
I cant see the triangles but look for 1 with a 90 degree angle. if it has 1 90 degree angle then that is you answer
In the given question, the contractor receives a payment of 1480.00. Then he has to pay for labours and materials and this amounts to 1111.74. On the remaining amount the contractor has to deduct 18% as overhead cost.
Then the amount of money left after the labour payments = 1480 - 1111.74
= 368.26
Now the overhead cost of 18% needs to be found from the amount of money left.
Then the overhead cost = 368.26 * 18/100
= 66.28
So the labour ost takes away 1111.74 and the overhead cost takes out 66.28 from the total payment of 1480.
Then the amount of profit made by the contractor = 368.26 - 66.28
= 301.98
So the contractor makes a profit of 301.98
Answer: The area of shaded section is 491.07 cm²
Step-by-step explanation:
Given: Radius of the circle = 25 cm
Now as shown in figure the shaded region is a quadrant.
Therefore the central angle is 90°
Now as we know
Area of sector is given by
where r is radius and
is central angle
So we have
![Area = \dfrac{22}{7} \times (25)^2\times \dfrac{90^\circ}{360^\circ} \\\\\Rightarrow Area= \dfrac{22}{7} \times 625 \times \dfrac{1}{4} \\\\\Rightarrow Area= \dfrac{11}{7} \times 625 \times \dfrac{1}{2} = 491.07cm^2](https://tex.z-dn.net/?f=Area%20%3D%20%5Cdfrac%7B22%7D%7B7%7D%20%5Ctimes%20%2825%29%5E2%5Ctimes%20%5Cdfrac%7B90%5E%5Ccirc%7D%7B360%5E%5Ccirc%7D%20%5C%5C%5C%5C%5CRightarrow%20Area%3D%20%20%5Cdfrac%7B22%7D%7B7%7D%20%5Ctimes%20625%20%5Ctimes%20%5Cdfrac%7B1%7D%7B4%7D%20%5C%5C%5C%5C%5CRightarrow%20Area%3D%20%20%5Cdfrac%7B11%7D%7B7%7D%20%5Ctimes%20625%20%5Ctimes%20%5Cdfrac%7B1%7D%7B2%7D%20%3D%20491.07cm%5E2)
Hence, the area of shaded section is 491.07 cm²