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dedylja [7]
2 years ago
9

Yeah I need help….. Do your work soldiers

Mathematics
2 answers:
Aloiza [94]2 years ago
8 0

I can’t, sir! I cannot leave my post to help with your math problems, over!

8_murik_8 [283]2 years ago
6 0
Here are the main properties of the Real Numbers. Real Numbers are Commutative, Associative and Distributive: Commutativeexample. a + b = b + a2 + 6 = 6 + 2.
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What compound inequality describes this graph
nadezda [96]

Answer:

0≥x<4

Step-by-step explanation:

first, let's look at this number line.

there is a closed circle at 0 and an open circle at 4. this means that 0 is included (≤ or ≥) and that 4 is not included (< or >).

these are the endpoints, meaning that in this compound inequality, the numbers next to the symbols are 0 and 4.

x is in the middle of this compound inequality.

0    x    4

now, we have to figure out the symbols in between. i wrote out our choices above for each number. the highlighted portion is greater than or equal to 0 and less than 4, so we can write this compound inequality as the following:

0≥x<4

x is greater than or equal to 0, but less than 4

4 0
3 years ago
Write the equation of the line that passes through the points (4, -6) and (-2,3).
Butoxors [25]
In point slope form, the answer would be y = - 3/2 x it’s one fraction
5 0
3 years ago
Read 2 more answers
Can someone please help me on this one​
Hunter-Best [27]

Answer:

c

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A scale drawing of Joshua's living room is shown below:
Nadya [2.5K]
To find the answer, first lets divide the width and length by the scale amount given, 2 cm.

Width: 4 cm / 2 cm = 2

Length: 6 cm / 2 cm = 3


After this, we multiply the result by the amount to scale up, in this case 4 feet.

Width: 2 * 4 = 8 feet


Length: 3 * 4 = 12 feet

Therefore the answer is the first option.
5 0
3 years ago
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
3 years ago
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