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Ivenika [448]
2 years ago
7

Which answer uses the distributive property to simplify the following? 3 × (5 + 8) A. (3 × 5) + (3 × 8) B. (3 × 5) × (3 × 8) C.

3 + 5 + 8
Mathematics
1 answer:
Andrei [34K]2 years ago
6 0

Answer:

A. (3 x 5) + (3 x 8)

Step-by-step explanation:

The Distributive property distributes the common factor that the numbers in the parenthesis are multiplied with.

Ex. A(B + C) will equal (A x B) + (A x C).

3 x (5 + 8) will equal (3 x 5) + (3 x 8).

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Step-by-step explanation:

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3 years ago
85,58,72,85,46,93 mean,mode,range,median​
Dima020 [189]

Answer:

mean= 73.167

mode= 85

range= 47

median​= 78.5

Step-by-step explanation:

46 58 72 85 85 93

mean= 73.167

mode= 85

range= 47

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4 0
3 years ago
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Change the subject of the formular to R
Dmitrij [34]

Answer:

r=s-t ÷ 2

Step-by-step explanation:

r2=s-t

r2÷2= s-t ÷2

r=s-t ÷2

5 0
4 years ago
write the equation of the perpendicular bisector that goes through the line segment with end points of A -1,-2 and B -2,-8
Dennis_Churaev [7]

Answer:

  2x +12y = -63 . . . in standard form

  y = -1/6x -21/4 . . . in slope-intercept form

Step-by-step explanation:

It is useful to find the midpoint of the segment. That is the average of the end points:

  M = ((-1, -2) +(-2, -8))/2 = ((-1-2)/2, (-2-8)/2) = (-3/2, -5)

It is also useful to find the changes in coordinates from B to A:

  Δ = A-B = (-1-(-2), -2-(-8)) = (1, 6)

From here, there are a couple of ways you can write the equation of the perpendicular line.

__

One way is to use the Δ values to compute the slope of the segment. The perpendicular line will have a slope that is the negative reciprocal of that.

  Δy/Δx = 6/1 = 6

  m = -1/6 . . . . . slope of the perpendicular line

Now we have a point and a slope for the desired line, so we can use a point-slope form of the equation for a line:

  y = m(x -h) +k

  y = (-1/6)(x -(-3/2)) +(-5)

  y = (-1/6)x -21/4 . . . . . . . . eliminate parentheses; point-slope form

__

Another way to write the perpendicular line is to use the Δ values directly as coefficients in the standard form equation:

  Δx(x -h) +Δy(y -k) = 0

  1(x -(-3/2)) + 6(y -(-5)) = 0 . . . substitute values

  x +6y +31.5 = 0 . . . . . . . . . . .collect terms

  2x +12y = -63 . . . . . . . . . . . . multiply by 2, put in standard form

7 0
3 years ago
3. What are the coordinates of the center and the length of the radius of the circle whose equation is(x + 1)^2 + (y - 5)^2 = 16
hram777 [196]

Given data:

The given equationn of the circle is (x + 1)^2 + (y - 5)^2 = 16.

The standard equation of the circle is,

(x-a)^2+(y-b)^2=r^2

The given equation can eb written as,

(x-(-1))^2+(y-5)^2=4^2

Compare the above equation with standard equation.

\begin{gathered} a=-1 \\ b=5 \\ c=4 \end{gathered}

Thus, the coordinate of centre is (-1, 5) and radius is 4.

7 0
1 year ago
Read 2 more answers
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