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Rama09 [41]
3 years ago
6

Use the data from problem:

Mathematics
1 answer:
navik [9.2K]3 years ago
5 0

Answer:

a) Sample mean: 48.71

Sample median: 48.3

Sample variance: 5.41

Sample standard deviation: 2.37

Step-by-step explanation:

a) Sample mean:

\bar{X}=\frac{1}{N} \sum X_i=\frac{1}{80}*3896.9=48.71

Sample median: M=48.3

Note: I order the data increasingly and take the value N / 2 = 40. In this way there are 39 values above and 39 values below the median.

Sample variance:

s^2=\frac{1}{N-1}\sum (X_i-\bar X)^2 =(\frac{1}{80-1})*427.74=5.41

Sample standard deviation

s=\sqrt{s^2}=\sqrt{5.41}=2.37

b)

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garri49 [273]

Answer:

a = 12

b = 9

c = 15

d = 17

e = 20

f = 11

g = 14

Step-by-step explanation:

Given that

(a + b) = 21 ...... (1)

(b + c) = 24 ........ (2)

(c + d) = 32 ........ (3)

(d + e) = 37 ........ (4)

(e + f) = 31 .......... (5)

(f + g) = 25 ........ (6)

(g + a) = 26 ......... (7)

Hence, adding all the equations we get, 2(a + b + c + d + e + f + g) = 196

⇒ (a + b + c + d + e + f + g) = 98 ...... (8)

Adding equations (2), (4) and (6), we get (b + c + d + e + f + g) = 86.

Therefore, from equation (8), we get a = 98 - 86 = 12 (Answer)

Adding equations (3), (5), and (7) we get,

a + c + d + e + f + g = 89

Hence, from equation (8), we have b = 98 - 89 = 9 (Answer)

Similarly, adding equations (1), (4), and (6) we get,

a + b + d + e + f + g = 83,

Hence, c = 98 - 83 = 15 (Answer)

Now, adding equations (2), (5) and (7), we get

a + b + c + e + f + g = 81. Hence, d = 98 -81 = 17 (Answer)

Adding equations (1), (3), and (6)

a + b + c + d + f + g = 78. Hence e = 98 - 78 = 20 (Answer)

Adding equations (2), (4), and (7)

a + b + c + d + e + g = 87. Hence f = 98 - 87 = 11 (Answer)

Adding equations (1), (3), and (5)

a + b + c + d + e + f = 84. Hence g = 98 - 84 = 14 (Answer)

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3 years ago
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