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Sloan [31]
4 years ago
10

Evaluate on lim x->0 (1-cosx) / x sinx

Mathematics
1 answer:
kozerog [31]4 years ago
7 0
\lim_{x \to 0}  \frac{1-\cos{x}}{x\sin{x}} 
\\
\\ \lim_{x \to 0}  \frac{1-\cos{x}}{x}  \frac{1}{\sin{x}} 
\\
\\\lim_{x \to 0}  \frac{1-\cos{x}}{x^2}  \frac{x}{\sin{x}} 
\\
\\\lim_{x \to 0}  \frac{1-\cos{x}}{x^2}  \frac{1}{\frac{\sin{x}}{x}} 
\\
\\\lim_{x \to 0}  \frac{1-\cos{x}}{x^2} \lim_{x \to 0}  \frac{1}{\frac{\sin{x}}{x}} 
\\
\\\lim_{x \to 0}  \frac{1-\cos{x}}{x^2}   \frac{1}{\lim_{x \to 0}\frac{\sin{x}}{x}} 
\\
\\ \frac{1}{2} \times \frac{1}{1} = \frac{1}{2}
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The answer is C.

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Select the correct answer.
sladkih [1.3K]

Answer:

A

Step-by-step explanation:

Because this ia so simple I don't even need to explain to waste my last few brain cells.

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Simplify: [(-17) + 4 ÷ 2] ÷ [8 ÷ (-4) + 4] = ?​
lions [1.4K]

\large{\underline{\underline{\textsf{\textbf{\purple{Solution \: : - }}}}}}

\begin{gathered} \\  \\ \quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) + 4 \div 2 \bigg] \div \bigg[8 \div  \bigg( - 8 \bigg) + 4 \bigg]}  \\  \\ \end{gathered}

\red \divideontimes According to the "BODMAS rule" firstly performing "division".

\begin{gathered} \\  \\ \quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) + \dfrac{4}{2} \bigg] \div \bigg[ \dfrac{8}{ - 8} + 4 \bigg]}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) +  \cancel{\dfrac{4}{2}} \bigg] \div \bigg[ \: \cancel{\dfrac{8}{ - 8}} + 4 \bigg]}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf \bigg[ \bigg( - 17 \bigg) +  2 \bigg] \div \bigg[ - 1 + 4 \bigg]}  \\  \\ \end{gathered}

\red \divideontimes Now, performing "addition and opening round brackets".

\begin{gathered} \\  \\\quad\dashrightarrow{\sf \bigg[ - 17 +  2 \bigg] \div \bigg[ - 1 + 4 \bigg]}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf \bigg[  \:  - 15 \:  \: \bigg] \div \bigg[  \:  \:  3\:  \: \bigg]}  \\  \\ \end{gathered}

\red \divideontimes Now, opening "square brackets".

\begin{gathered} \\  \\ \quad\dashrightarrow{\sf { - 15  \div 3}}  \\  \\ \end{gathered}

\red \divideontimes Now, "dividing 15 by 3".

\begin{gathered}\\ \\ \quad\dashrightarrow{\sf {\dfrac{ - 15}{3} }}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\sf { \cancel{\dfrac{ - 15}{3}}}}  \\  \\ \end{gathered}

\begin{gathered}\quad\dashrightarrow{\underline{\underline{ \sf{\red{ - 5}}}}}  \\  \\ \end{gathered}

\begin{gathered}\bigstar{\underline{\boxed{\bf{\purple{Answer =  - 5}}}}}  \\  \\ \end{gathered}

∴ The Answer is -5.

\begin{gathered}\end{gathered}

\large{\underline{\underline{\textsf{\textbf{\purple{Learn More \: : - }}}}}}

\underline{\underline{\pmb{\mathbb{\red{BODMAS \: :}}}}}

<u>BODMAS</u> rule is an acronym used to remember the order of operations to be followed while solving expressions in mathematics.

It stands for :-

  • ↠ B - Brackets,
  • ↠ O - Order of powers or roots,
  • ↠ D - Division,
  • ↠ M - Multiplication 
  • ↠ A - Addition,
  • ↠ S - Subtraction.

It means that expressions having multiple operators need to be simplified from left to right in this order only.

\rule{200}2

\underline{\underline{\pmb{\mathbb{\red{BODMAS \:  RULE \: :}}}}}

First, we solve brackets, then powers or roots, then division or multiplication (whatever comes first from the left side of the expression), and then at last subtraction or addition.

  • ↠ Addition (+)
  • ↠ Subtraction (-)
  • ↠ Multiplication (×)
  • ↠ Division (÷)
  • ↠ Brackets ( )

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

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Maksim231197 [3]

Answer:

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Step-by-step explanation:

The range is all non-negative numbers.

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  range: [0, ∞)

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