2 years ago

Divide.

Mathematics

1 answer:

slavikrds [6]2 years ago

7 0

Answer:

(24y^3x-20y^5x^2)/(-3y^5x^2)

= y^3x(24-20y^2x))/(-3y^5x^2)

=(24-20y^2x)/(-3y^2x)

=(24/(-3y^2x))-((20y^2x)/(-3y^2x))

=(-8/y^2x)-(-20/3)

=-8/y^2x + 20/3

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