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GenaCL600 [577]
3 years ago
10

Find the area of this triangle

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0

Answer:

15

Step-by-step explanation:

A triangle's area is its base times height divided by 2.

\frac{bh}{2}=\frac{5*6}{2}=\frac{30}{2}=15

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Is 7 - -4 positive or negative?<br> positive<br> negative
djverab [1.8K]

Answer:

Positive.

Step-by-step explanation:

When you see two negative signs directly next to each other (as shown in the given expression), it will become a positive sign:

7 - (-4) = 7 + 4 = 11

Positive is your answer.

* To be fair, even if there is only one negative sign, the answer will still be positive, however, I am assuming you are suggesting only the sign, and not the answer.

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7 0
3 years ago
Simplify (x2y)3.<br><br> x2y3<br> x5y3<br> x6y3
Andrews [41]

Answer:

3x2^y

Step-by-step explanation:

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3 years ago
Find the angle x in this triangle
Romashka-Z-Leto [24]

Answer:

x = 36

Step-by-step explanation:

<em>A triangle has 180°</em>.

That <em>third angle is 360 - 8x</em>.

So the equation is: <em>180 = 2x + x + 360 - 8x</em>.

Simplify: 180 = -5x + 360

Add/Subtract: 5x = 180

Divide: x = 36.

7 0
3 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
I am in 8th grade and i need help on Pre Algebra could you help me?
Morgarella [4.7K]

Answer:

Sure, what do you need help on?

7 0
3 years ago
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