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3 years ago

Mr. Herrera has 4 cups of raisins to serve to his students as a snack. How many 19 of a cup of servings can Mr. Herrera make?

Mathematics

1 answer:

MArishka [77]3 years ago

4 0

Answer: The answer is 4 * 9 = 36, So Mr. Herrera can make 36 sevings.

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Find the pre-image of 5 in the function g(x) = 5x?

Vlada [557]

Answer:

pre-image also means domain

so the value of X is 5

so 5x = 5×5

the answer is 25

5 0

2 years ago

The price of an item has been reduced by 15%. The original price was $93.

alexandr402 [8]

Answer:

$79.05

Step-by-step explanation:

Multiply 93 times 15%, which gets you $13.95.

Then subtract 13.95 from the 93 (93 - 13.95).

3 0

3 years ago

A box contains 5 plain pencils and 7 pens. A second box contains 3 color pencils and 3 crayons. One item from each box is chosen

Andru [333]

Multiply the two desired probabilities to find the answer.

5/12 is the probability for the plain pencil since there are 5 pencils out of 12 total items.

1/2 is the probability for the colored pencil since there are 3 colored pencils out of 6 total items. 3/6 simplifies to 1/2.

5/12*1/2= 5/24

Final answer: 5/24

8 0

2 years ago

For the function g(x)=3-8(1/4)^2-x

Reika [66]

Using function concepts, it is found that:

a) The y-intercept is y = 2.5.

b) The horizontal asymptote is x = 3.

c) The function is decreasing.

d) The domain is $(-\infty,\infty)$ and the range is $(-\infty,3)$ .
e) The graph is given at the end of the answer.

------------------------------------

The given function is:

$g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}$

------------------------------------

Question a:

The y-intercept is g(0), thus:

$g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5$

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

$\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3$

--------------------------------------------------

$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty$

Thus, the horizontal asymptote is x = 3.

--------------------------------------------------

Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

--------------------------------------------------

Question d:

Exponential function has no restrictions in the domain, so it is all real values, that is $(-\infty,\infty)$ .
From the limits in item c, the range is: $(-\infty,3)$

--------------------------------------------------

The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0

2 years ago

Which of the following polynomials is in standard form?

arsen [322]

A........................

5 0

2 years ago