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guapka [62]
2 years ago
9

If the length of a rectangle is 4 more than the width and if the perimeter of the rectangle is 52, what is the width of the rect

angle? O 11 O 12 O 15 0 24​
Mathematics
1 answer:
Ymorist [56]2 years ago
5 0

Answer:

11

Step-by-step explanation:

Perimeter is figured out by adding all 4 sides.

Width of 11 + width 11 + length 15 + length 15 = 52

And the length of 15 is 4 more than the width of 11

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11. John puts a fence around his rectangular backyard. The width of his backyard is 10 feet. He
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Length = 20 ft

If he uses 60 ft of fencing to line his rectangular backyard, then the perimeter is 60 ft.

Perimeter formula is ((Width × 2) + (Length × 2))

10 × 2 = 20

20 × 2 = 40

40 + 20 = 60

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2 years ago
Find the value of x by finishing solving the system shown below.
Andreas93 [3]

Answer:

x = 10

Step-by-step explanation:

Since both equations give y in terms of x, equate the right sides

3x - 28 = - 2x + 22 ( add 2x to both sides )

5x - 28 = 22 ( add 28 to both sides )

5x = 50 ( divide both sides by 5 )

x = 10

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3 years ago
10. (04.01)
never [62]

Answer:

A] A function is a special type of relation for which there is a rule that pairs each input with exactly one output.

Step-by-step explanation:

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3 years ago
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8 is 75% of what number
lisov135 [29]

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10.6

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8 0
3 years ago
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A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following
kiruha [24]

Answer:

<em>After </em><em>47</em><em> days she will have more than 90 trillion pennies.</em>

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

1,2,4,8,16,32,.....

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

S_n=\dfrac{a(r^n-1)}{r-1}

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}

\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}

\Rightarrow 90\times 10^{12}\le 2^n-1

\Rightarrow 2^n\ge 90\times 10^{12}+1

\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)

\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)

\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}

\Rightarrow n \ge 46.4

\Rightarrow n\approx 47


8 0
3 years ago
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