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2 years ago

9

If the length of a rectangle is 4 more than the width and if the perimeter of the rectangle is 52, what is the width of the rect

angle? O 11 O 12 O 15 0 24

1 answer:

Ymorist [56]2 years ago

5 0

Answer:

11

Step-by-step explanation:

Perimeter is figured out by adding all 4 sides.

Width of 11 + width 11 + length 15 + length 15 = 52

And the length of 15 is 4 more than the width of 11

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Susan had 8/9 acres of land. She planted 2/5 of it with corn. How many acres did she plant with corn?

Sergio039 [100]

$\bf \textit{how much is }\frac{2}{5}\textit{ of }\frac{8}{9}?\implies \cfrac{8}{9}\cdot \cfrac{2}{5}\implies \cfrac{16}{45}$

that's how many acres she planted with corn.

6 0

3 years ago

A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.

Vlada [557]

Answer:

a) $y=12000(2)^{\frac{t}{50}}$

b) Approx. 27,569 bacteria

c) About 103 minutes

Step-by-step explanation:

a)

This will follow exponential modelling with form of equation shown below:

$y=Ab^{\frac{t}{n}}$

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

$y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}$

b)

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

$y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76$

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>

<u></u>

c)

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

$y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103$

After about 103 minutes, there will be 50,000 bacteria

4 0

3 years ago

Which pairs of quadrilaterals can be shown to be congruent using rigid motions?

Misha Larkins [42]

Answer:

1 and 2 are not congruent; 1 and 3 are congruent; 1 and 4 are congruent; 2 and 3 are not congruent; 2 and 4 are not congruent; 3 and 4 are congruent.

Step-by-step explanation:

From the diagram, we can see that the angle measures and side measures of figures 1, 3 and 4 are the same. This means that these three figures are congruent. Figure 2, however, is not congruent to any of the other 3.

5 0

3 years ago

Read 2 more answers

V1-v2\t solve formula for v1

vitfil [10]

Answer:

Uwm am I famous but I'm doin dis for free points sowwy

8 0

3 years ago

Hector has 3/4 hour to spend his homework. He wants to spend 1/3 of this time on math homework, 10 minutes of his time on readin

DENIUS [597]

Answer:

20 minutes

Step-by-step explanation:

Remember that

$1\ h=60\ mi$

we know that

Hector has 3/4 hour to spend his homework

Convert to minutes

$\frac{3}{4}(60)=45\ min$

so

1) He wants to spend 1/3 of this time on math homework

To find out the time on math homework, multiply 45 minutes by 1/3

$45(\frac{1}{3})=15\ min$

2) He wants to spend 10 minutes of his time on reading homework

3) He wants to spend the remaining time on science homework

The time spend on math homework plus the time spend reading homework, plus the time spend on his science homework must be equal to 45 minutes

Let

x ----> the time spend on his science homework

$15+10+x=45$

Solve for x

$25+x=45\\x=45-25\\x=20\ min$

3 0

3 years ago