This is a geometric sequence as each term is a constant ratio of the previous term, called the common ratio...
2a^2b/2a=(2a^3b^2)/(2a^2b)=ab and the first term is 2a
So the rule is:
a(n)=2a(ab)^(n-1)
a(6)=2a(ab)^5=2a^6(b^5)
We cannot know for sure if this series is infinite or not. It would depend on what the values of a and b were.
If EITHER a^2 or b^2 is less than one the series would be finite (and technically a sequence and not a series),and a sum could be found. If a^2 AND b^2 are greater than one it is an infinite series whos sum diverges....