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2 years ago

76. 30 students at a sports event are

Mathematics

1 answer:

katrin2010 [14]2 years ago

4 0

Answer:

75 students

Step-by-step explanation:

So firstly lets make convert these words to alegbra :

30 people are 40%of the total students at the event meaning that the following equation can be made :

30 = 40% of x (x is the unknown amount of students there)

30 = 40% * x

30 = 0.4x (we can convert the precentage into a decimal by dividing by 100)

Now that we have the equation that 30 = 0.4x we can evalute it and find x :

30=0.4x

30/0.4=0.4x/0.4 (divide by 0.4 on both sides)

75=x

So thats how we get that 75 students were in the event in total.

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Using bootstrap, the standard error is: 0.050

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Sample A Sample B

$x_A = 30$ $x_B = 50$

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Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

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$p_A = 0.30$

The proportion of B

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$p_B = 0.20$

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$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

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$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$