Distributive proeprty
wait
combein elike terms
4(1m+3+5m)=4(5m+1m+3)=4(6m+3)
if we distribute
reemmber that a(b+c)=ab+ac
4(6m+3)=4(6m)+4(3)=24m+12
A. 24m+12 and 12(2m+1)
B. distributive property
C. if m=1, we get 36=36
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5
Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students
Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students
Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68
Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
There u just needed to search the formula
108-271+215-_____=-103
Im going to combine the first thee numbers and replace the blank with a variable, lets use x.
52 - x=-103
now I am going to subtract 52 on both sides to get the variable alone
-x=-155
Im going to multiply both sides to eliminate the negitive in the variable
x=155
If you want to check just plug 155 into the blank
108-271+215-155=-103
-163+215-155=-103
52-155=-103
-103=-103
so after checking work the blank is equal to 155.
Answer:
440 hours
Step-by-step explanation:
In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:
Hours of the second cycle= Total time in service- time Airworthiness Directive
=468-454=14
Then we have 14 hours of service and need to accumulate the rest to complete 454. It is
454-14=440
Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .