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Masja [62]
3 years ago
10

Please help me ive never done one like this

Mathematics
1 answer:
inessss [21]3 years ago
5 0

Given:

DE = (6x - 9) cm

EF = (4x + 4) cm

LM = 14 cm

MN = 16 cm

To find:

The value of x.

Solution:

<em>If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.</em>

$\Rightarrow \frac{DE}{EF} =\frac{LM}{MN}

$\Rightarrow \frac{6x-9}{4x+4} =\frac{14}{16}

Do cross multiplication.

$\Rightarrow 16( {6x-9})=14 ({4x+4} )

$\Rightarrow 96x-144=56 x+56

Add 144 on both sides.

$\Rightarrow 96x-144+144=56 x+56+144

$\Rightarrow 96x=56 x+200

Subtract 56x from both sides.

$\Rightarrow 96x-56x=56 x+200-56x

$\Rightarrow 40x=200

Divide by 40 on both sides, we get

$\Rightarrow x=5

The value of x is 5.

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Too stoned help pls
podryga [215]
Distributive proeprty
wait
combein elike terms
4(1m+3+5m)=4(5m+1m+3)=4(6m+3)

if we distribute
reemmber that a(b+c)=ab+ac
4(6m+3)=4(6m)+4(3)=24m+12




A. 24m+12 and 12(2m+1)
B. distributive property
C. if m=1, we get 36=36
3 0
3 years ago
In an Algebra II class with 135 students, the final exam scores have a mean of 72.3 and standard deviation 6.5. The exams on the
gregori [183]
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5

Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students

Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students

Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68

Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
4 0
3 years ago
Please answer the image below .
mojhsa [17]
There u just needed to search the formula

8 0
3 years ago
Read 2 more answers
108 - 271 + 215-_____= -103
kupik [55]
108-271+215-_____=-103
Im going to combine the first thee numbers and replace the blank with a variable, lets use x. 
52 - x=-103
now I am going to subtract 52 on both sides to get the variable alone
-x=-155
Im going to multiply both sides to eliminate the negitive in the variable
x=155
If you want to check just plug 155 into the blank
108-271+215-155=-103
-163+215-155=-103
52-155=-103
-103=-103

so after checking work the blank is equal to 155.


5 0
4 years ago
An aircraft has a total time in service of 468 hours. The Airworthiness Directive given was initially complied with at 454 hours
Georgia [21]

Answer:

440 hours

Step-by-step explanation:

In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:

Hours of the second cycle= Total time in service- time Airworthiness Directive

=468-454=14

Then we have 14 hours of service and need to accumulate the rest to complete 454. It is

454-14=440

Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .

6 0
3 years ago
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