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Olin [163]
3 years ago
14

Solve for X . You must show all of your work to receive credit.

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

x = 6

Step-by-step explanation:

∠WVU lies outside the circle and the sides are tangents. The measure of the tangent- tangent angle is

∠WVU = 0.5( major arc - minor arc), that is

5x + 17 = 0.5(37x + 5 - (23x - 5)) = 0.5(37x + 5 - 23x + 5) = 0.5(14x + 10), so

5x + 17 = 7x + 5 ( subtract 7x from both sides )

- 2x + 17 = 5 ( subtract 17 from both sides )

- 2x = - 12 ( divide both sides by - 2 )

x = 6

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Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
Find the area of the following shape. Show work.
Serga [27]

Answer:

The total area:

12 units²

Step-by-step explanation:

There are three parts on this shape:

1 big right triangle

1 rectangle

1 small right triangle

  • Big right triangle:

area = (4*4)/2 = 16/2 = 8units²

  • Rectangle:

area = 2*1 = 2units²

  • Small right triangle:

area = (2*2)/2 = 2units²

  • Total area

8+2+2 = 12 units²

6 0
3 years ago
Solve the system of linear equations and show your work.<br> −8x+5y=26<br> 9x−3y=−3
maks197457 [2]
X is 7 and y is 2 I am pretty sure
6 0
3 years ago
An auditorium has 20 seats on the first row, 24 seats on the second row, 28 seats on the third row, and so on and has 30 rows of
Lilit [14]

Answer:

140

Step-by-step explanation:

20+4(s)=

20+4(30)=

20+ 120=

140

8 0
2 years ago
A circle has a diameter of 26 feet. Find its circumference and area.
iogann1982 [59]

Answer: 81.64 feet

Step-by-step explanation:

Circumference of a circle = pi * diameter

Circumference of a circle = 3.14 * 26 feet

Circumference of a circle = 81.64 feet

5 0
2 years ago
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