What is the quotient of 35 divided by 7

Which order pair is a solution to the system of linear equations -4+y=8 and x-5y=17?

andreev551 [17]

Hello!

To find this ordered pair, we solve for x and y and put them together in an ordered pair.

-4+y=8

x-5y=17

Let's solve the first equation for y.

y= 12

Now, let's plug 12 into the second equation for y.

x-5(12)=17

x-60=17

x=77

Therefore, our ordered pair is (77,12)

I hope this helps!

4 0

3 years ago

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A cell phone company offers service for a flat rate of 20$ per month,plus 3 cents a minute. Which expression could represent the

ElenaW [278]

Answer:

20 + 3x = x

Step-by-step explanation:

4 0

3 years ago

What is x - 3(1-x) = 47 - x

lozanna [386]

Solve for x by simplifying both sides of the equation, then isolating the variable.

x = 10

7 0

4 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

A 10-yr-old competes in gymnastics. For several competitions, she received the following "All-Around" scores: 35.5, 36.3. 36.6,

Delicious77 [7]

Answer:

The child needs a score of 37.2 to move up to the next level of the competition.

Step-by-step explanation:

The mean is the sum of all scores divided by the number of competions. So

$M = \frac{S}{T}$

In which S is the sum of all her scores and T is the number of competitions.

The child has five competions:

Which means that $T = 5$

She has to get a mean of at least 36.5, so $M = 36.5$

Her scores are: 35.5, 36.3. 36.6, and 36.9. Her last score, i am going to call x. So

$S = 35.5 + 36.3 + 36.6 + 36.9 + x = 145.3 + x$

The child needs a score of _____ to move up to the next level of the competition.

This score is x. So

$M = \frac{S}{T}$

$36.5 = \frac{145.3 + x}{5}$

$145.3 + x = 36.5*5$

$x = 37.2$

3 0

3 years ago