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3 years ago

13

What is the quotient of 35 divided by 7

1 answer:

loris [4]3 years ago

4 0

5 is the answer buddy

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Find the product and write ot in the lowest terms. 6 over 7 × 9 over 4

Nikitich [7]

Answer:

27/14

Step-by-step explanation:

you can cross multiply and simplify before you start. that way it makes it a lot easier

7 0

4 years ago

Elena is paid a constant rate for each hour she works. The table shows the amounts of money that Elena earned for various amount

Nikolay [14]

Constant rates are used to illustrate linear functions.

The average rate of change is $9.0 per hour
The function that models the table is: $\mathbf{f(x) = 9x }$
The amount earned in 7.5 hours is $67.5

<u>(a) The average rate of change</u>

This is calculated using:

$\mathbf{Rate = \frac{y_2 -y_1}{x_2 -x_1}}$

So, we have:

$\mathbf{Rate = \frac{31.5-22.50}{3.5 - 2.5}}$

$\mathbf{Rate = \frac{9}{1.0}}$

$\mathbf{Rate = 9.0}$

Hence, the average rate of change is $9.0 per hour

<u>(b) A function that models the table of values</u>

Let x represent hours, and y represent the earnings.

So, we have:

$\mathbf{y =m (x - x_1) + y_1}$

Where:

m =Rate = 9.0

So, we have:

$\mathbf{y = 9(x - 2.5) + 22.5}$

Expand

$\mathbf{y = 9x - 22.5 + 22.5}$

$\mathbf{y = 9x }$

Represent as a function

$\mathbf{f(x) = 9x }$

Hence, the function that models the table is: $\mathbf{f(x) = 9x }$

<u>(c) Amount earned for 7.5 hours</u>

This means that x = 7.5

So, we have:

$\mathbf{f(7.5) = 9 \times 7.5 }$

$\mathbf{f(7.5) = 67.5}$

Hence, the amount earned in 7.5 hours is $67.5

Read more about constant rates at:

brainly.com/question/23184115

4 0

2 years ago

Of the students at .... Middle School, fewer than eighty-four students said that they have never played Call Of Duty. This is ab

gladu [14]

640 students where surveyed

5 0

3 years ago

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

6.

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

7 0

3 years ago

Please help with this question! 25 Points!

AlexFokin [52]

Answer:

Domain - (0,1,2,3,4) Range - (32,27,22,17,12)

Domain - (0,1,2,3,4) Range - (36,32,28,24,20)

Step-by-step explanation:

The # of knots is actually the X values which is also the definition of the word, "Domain" whilst the Length of the ropes is the y values, aka the range.

6 0

3 years ago