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2 years ago

(Picture) MULTIPLYING POLYNOMIALS AND SIMPLIFYING EXPRESSIONS PLEASE HELP!!!!

Mathematics

1 answer:

kvv77 [185]2 years ago

3 0

Answer:

Answer: Third option is the right answer.

Step-by-step explanation:

First we the write the expression

$(a+b)(a^{2}+b^{2}-ab)$

Now teacher says that the product of these polynomials will result in the sum of $a^{3}+b^{3}$

Now the teacher ask if we put the value of a = 2x and b = 1 then what will be the expression look like.

$(2x+1)\left [ (2x)^{2}+(1^{2})-(2x)(1)\right ]$

= $(2x+1)(4x^{2}+1-2x)$

So third option is looking like our expression.

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Drag steps of the solution into order to solve for x in the equation 5(x – 7) = 50.

ch4aika [34]

Answer:

x=17

Step-by-step explanation:

5x-35=50

+35 +35

_________

5x=85

÷5 ÷5

__________-

x=17

Hope this helps :D

And if u could pls give me brainly tysm if u do!!

8 0

2 years ago

Find the mean of the first 7 odd prime number?

bekas [8.4K]

Answer: 75/7 or 10.71 (rounded)

Step-by-step explanation:

Mean = Average

To find the average you should add all the numbers together and then divide it by the amount of numbers.

In this question, the formula is $\frac{n_1+n_2+n_3+n_4+n_5+n_6+n_7}{7}$

----------------------------------------------------------------------------------------

The list of the first 7 odd prime numbers:

3, 5, 7, 11, 13, 17, 19

Now, add them together

3+5+7+11+13+17+19=75

Divide the sum by 7

75÷7=75/7=10.71 (rounded)

Hope this helps!! :)

Please let me know if you have any questions

6 0

2 years ago

Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

2 years ago

HELP HELP HELP I NEED HELP

iris [78.8K]

Answer:

Step-by-step explanation:

cause it a circle and it will need a little more then the number it is

4 0

2 years ago

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Completing the FAFSA could help decide whether a studentdeserves a merit-based awardshould receive student-specific financial ai

beks73 [17]

FAFSA -- free application for federal student aid.....so answer would be student specific financial aid

3 0

3 years ago

Read 2 more answers