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allsm [11]
2 years ago
8

Elena is paid a constant rate for each hour she works. The table shows the amounts of money that Elena earned for various amount

s of
time that she worked.

Mathematics
1 answer:
Nikolay [14]2 years ago
4 0

Constant rates are used to illustrate linear functions.

  • The average rate of change is $9.0 per hour
  • The function that models the table is: \mathbf{f(x) = 9x }
  • The amount earned in 7.5 hours is $67.5

<u>(a) The average rate of change</u>

This is calculated using:

\mathbf{Rate = \frac{y_2 -y_1}{x_2 -x_1}}

So, we have:

\mathbf{Rate = \frac{31.5-22.50}{3.5 - 2.5}}

\mathbf{Rate = \frac{9}{1.0}}

\mathbf{Rate = 9.0}

Hence, the average rate of change is $9.0 per hour

<u>(b) A function that models the table of values</u>

Let x represent hours, and y represent the earnings.

So, we have:

\mathbf{y =m (x - x_1) + y_1}

Where:

m =Rate = 9.0

So, we have:

\mathbf{y = 9(x - 2.5) + 22.5}

Expand

\mathbf{y = 9x - 22.5 + 22.5}

\mathbf{y = 9x }

Represent as a function

\mathbf{f(x) = 9x }

Hence, the function that models the table is: \mathbf{f(x) = 9x }

<u>(c) Amount earned for 7.5 hours</u>

This means that x = 7.5

So, we have:

\mathbf{f(7.5) = 9 \times 7.5 }

\mathbf{f(7.5) = 67.5}

Hence, the amount earned in 7.5 hours is $67.5

Read more about constant rates at:

brainly.com/question/23184115

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Answer:

x = 15

Step-by-step explanation:

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So to solve for the missing angle we can solve for x using the Pythagorean Theorem

The Pythagorean theorem states that the sum of the two legs squared equal the hypotenuse squared

Knowing this we can create an equation to solve for x

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now we solve for x

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Following are the dependent variables:

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<em>2. The species of trees in the orchard.</em>

Reason:

The exercise scientist is looking for the effects of a chemical between an apple crop to which it is administered and another to which it is not, 4 options are presented, of which it is essential to count as a variable the amount of water each Orchard and tree species in the orchard, since they can generate alterations in the results, the other two variables of the exercise such as number of apples and size of the orchards are not significant and their variations do not affect the scientist's objective.

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