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1 year ago

7

If a coin is tossed, a die is rolled, and a candy is taken from

1 answer:

vesna_86 [32]1 year ago

6 0

Answer:

⅛

Step-by-step explanation:

There are two sides of a coin which means that the profanity of getting one side of the coin is ½.

There are 14 candies in total of which 7 are red, meaning that the probability of getting a red candy is 7/14, which is the same as ½.

There are 6 sides to a die, of which 3 sides contain the odd numbers 1,3 and 5. This would mean that the probability of getting an odd number on the die is 3/6, which is the same as ½.

Now to work out the probability of getting a red candy, a heads and an odd number on the die, you have to times the probability of each together to get you final answer.

So it will be, ½×½×½=⅛

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Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

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pychu [463]

Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

$m\angle RPS=90^\circ$ [Right angle]

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$(5x+15)=90$

$5x=90-15$

$5x=75$

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$x=\dfrac{75}{5}$

$x=15$

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

$m\angle RQP=(2x+3)^\circ$

Putting $x=15$ , we get

$m\angle RQP=(2(15)+3)^\circ$

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$m\angle RQP=33^\circ$

Therefore, the measure of angle RQP is 33 degrees.

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2 years ago

If M∠ ABD =64 and M∠CBD=30 then M∠ABC= <br> Need help

Leno4ka [110]

Answer:

$\displaystyle m\angle ABC = 34^\circ$

Step-by-step explanation:

∠ABD is the sum of the angles ∠ABC and ∠CBD. In other words:

$\displaystyle m\angle ABD = m\angle ABC + m\angle CBD$

Substitute in known values:

$\displaystyle \left(64^\circ\right) = m\angle ABC + \left(30^\circ\right)$

And subtract. Hence:

$\displaystyle m\angle ABC = 34^\circ$

In conclusion, ∠ABC measures 34°.

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Answer:

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Step-by-step explanation:

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