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belka [17]
2 years ago
7

If a coin is tossed, a die is rolled, and a candy is taken from

Mathematics
1 answer:
vesna_86 [32]2 years ago
6 0

Answer:

⅛

Step-by-step explanation:

There are two sides of a coin which means that the profanity of getting one side of the coin is ½.

There are 14 candies in total of which 7 are red, meaning that the probability of getting a red candy is 7/14, which is the same as ½.

There are 6 sides to a die, of which 3 sides contain the odd numbers 1,3 and 5. This would mean that the probability of getting an odd number on the die is 3/6, which is the same as ½.

Now to work out the probability of getting a red candy, a heads and an odd number on the die, you have to times the probability of each together to get you final answer.

So it will be, ½×½×½=⅛

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<h3><u>Question:</u></h3>

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.

The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

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Dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

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Cylinders A and B are similar solids.

The base of cylinder A has a circumference of 4 \pi units

The base of cylinder B has an area of 9 \pi units

Let "x" be the required factor

From given question,

Dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B

Therefore, we can say,

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }

<h3><u>Cylinder A:</u></h3>

The circumference of base of cylinder (circle ) is given as:

C = 2 \pi r

Where "r" is the radius of circle

Given that  base of cylinder A has a circumference of 4 \pi units

Therefore,

4 \pi = 2 \pi r\\\\r = 2

Thus the dimension of cylinder A is radius = 2 units

<h3><u>Cylinder B:</u></h3>

The area of base of cylinder (circle) is given as:

A = \pi r^2

Given that,  the base of cylinder B has an area of 9 \pi units

Therefore,

\pi r^2 = 9 \pi\\\\r^2 = 9\\\\r = 3

Thus the dimension of cylinder B is radius = 3 units

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }\\\\2 \times x = 3\\\\x = \frac{3}{2}

Thus dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

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Answer:

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